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DENIUS [597]
3 years ago
8

The smallest number in the list {1.0101, 1.0011, 1.0110, 1.1001, 1.1100} is? How do you know?

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:

By multiplying each with 10 i think soo

user100 [1]3 years ago
7 0
The smallest number in the list is 1.0011 . how i know is that if you multiply each number by 100, 1.0011 turns into 100.11 which is the smallest out of all
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What is the area of the trapezoid shown below?
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The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
A price decreases from $254 to $213.36 . What is the percent of change?
sattari [20]

16% discount, this is because 213.36-254 over the original price (254) times 100% equals -16%

8 0
3 years ago
Evaluate x+16, when x=8
Hatshy [7]

Answer:

24

Step-by-step explanation:

x + 16

8 + 16

= 24

You just plug in 8 in the x place. Hope this helps, thank you !!

7 0
3 years ago
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