123a
123q
123w
123e
123r
123t
123y
123u
123i
123o
123p
123s
123d
123f
123g
123h
123j
123k
I thought this would be easy lol, I tried, sorry for not getting an answer
Answer:
20/24
Step-by-step explanation:
let the variable be x and x-4
5/6 = x-4/x
cross multiply
5x = 6x - 24
24= x
thus, x is 24 and x-4 is 20
<u>20/24</u>
Answer:
-3t > 11
Step-by-step explanation:
hope this helps :)
Answer:
5 units
Step-by-step explanation:
3x + 4y = 8
4y = -3x+8
y = -3/4+2
The shortest distance between a point and a line is the perpendicular line.
Slope of the perpendicular line: 4/3 and point (-3,-2)
b = -2-(4/3)(-3) = 2
Equation of the perpendicular line: y=4/3x+2
y is equal y
4/3x+2= -3/4x+2
4/3x +3/4x = 2-2
x = 0
Plug x=0 into one of the equations to find y
y = 4/3(0) + 2
y = 2
(0,2) and (-3,-2)
Distance = sqrt [(-3-0)^2 + (-2-2)^2]
Sqrt (-3)^2+ (-4)^2
Sqrt 25 = 5
Answer:
44,39 in
Step-by-step explanation:
To find the space diagonal (whatever it's called in English) you begin looking at the bottom of the box. We want to know the diagonal since the diagonal is one of the sides of the other triangle.
To do this we can start by using trigonometry. (SOH-CAH-TOA)
We need to use Sin t. (Since we wanna know the hypothenuse and we have the opposite.)
So...
Sin(40) = 24 in ÷ <em>h</em>
Then we need to actually be able to calculate this, which we will be able to do if we multiply with h on both sides.
hSin(40) = 24 in
Like that. And now we can divide both sides with Sin(40). So we calculate 24 in devided by Sin(40).
h = 24 in ÷ Sin(40) = 37,34 in
Okay so now we now the diagonal, 37,34 in. Now we can use Pythagorean theorem. (2a+2b=2c and c = square root of (2a+2b))
37,34 in^(2) + 24 in^(2) = 1970,28
And now we take the square root of 1970,28.
Which is about 44,39 in.
<em>If you're not familiar with these concepts I suggest you</em><em> </em><em>search</em><em> </em><em>them</em><em> </em><em>up</em><em>.</em>
