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3 years ago

I don't understand this

Mathematics

1 answer:

Mamont248 [21]3 years ago

4 0

Answer:

you have to use graph to make it bro

Step-by-step explanation:

hope it will help you

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In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat

Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

427 had paid for coaching courses and the remaining 2733 had not.

This means that $n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147$

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

8 0

3 years ago

Translate this sentence into an equation.<br><br> The difference of Mai's age and 12 is 60

daser333 [38]

Answer: 72

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How did Bill spend longer

JulsSmile [24]

How did bill spend longer .. days ... ? what

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3 years ago

They drove 4 hours on Day Three. What was their average speed on the third day?Gabriel’s family went on a road trip through upst

MA_775_DIABLO [31]

Answer:

they drove a total of 12 hours

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2 years ago

What is the area of the space

Nikitich [7]

check the picture below.

since we know is a rectangle, then we can simply find a width and a length, say hmmm CD and CB and get their product, recall that the area of a rectangle is width*length.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ C(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad D(\stackrel{x_2}{-7}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ CD=\sqrt{[-7-(-4)]^2+[1-(-3)]^2}\implies CD=\sqrt{(-7+4)^2+(1+3)^2} \\\\\\ CD=\sqrt{(-3)^2+4^2}\implies CD=\sqrt{9+16}\implies \boxed{CD=5}\\\\ -------------------------------$

$\bf C(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{3}) \\\\\\ CB=\sqrt{[4-(-4)]^2+[3-(-3)]^2}\implies CB=\sqrt{(4+4)^2+(3+3)^2} \\\\\\ CB=\sqrt{8^2+6^2}\implies CB=\sqrt{64+36}\implies \boxed{CB=10}\\\\ -------------------------------\\\\ \stackrel{\textit{area of rectangle}}{CD\cdot CB}\implies 50$

4 0

3 years ago

I don't understand this ​

I don't understand this