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Oxana [17]
3 years ago
8

The melting of ice is considered a physical change because:

Chemistry
1 answer:
crimeas [40]3 years ago
8 0

Answer: C Hope it helps

Explanation:

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ILL GIVE 30 POINTS TO THE BRAINIEST
Nikitich [7]

Answer:

Every chemical equation follows to the law of conservation of mass, which states that matter cannot be created or destroyed. When you have an equal number of atoms of an element is present on both sides of a chemical equation, the equation is balanced therefore it is following the law of conservation of mass.

Explanation:

5 0
3 years ago
Read 2 more answers
Balanced equation of potassium chloride and ammonium nitrate; it’s types, net and observation
ASHA 777 [7]

Potassium chloride reacts with ammonium nitrate to give ammonium chloride and potassium nitrate.

This is a type of double displacement reaction. The balanced chemical equation can be represented as,

KCl(aq)+NH_{4}NO_{3}(aq)-->NH_{4}Cl(aq)+KNO_{3}(aq)

Total ionic equation for this reaction will be,

K^{+}(aq)+Cl^{-}(aq)+NH_{4}^{+}(aq)+NO_{3}^{-}(aq)--> K^{+}(aq)+NO_{3}^{-}(aq)+NH_{4}^{+}(aq)+Cl^{-}(aq)

There is no apparent reaction as this reaction is not accompanied by the formation of a gas or a solid precipitate. We cannot observe any visual reaction as there is not net reaction taking place. All the ions remain as spectator ions.

5 0
4 years ago
What are two elements that produce background radiation on earth and what do their decay equations look like?
Vlada [557]
1. U₂₃₈→α→Th₂₃₄(UX₁) 
<span>2. Th₂₂₈→α→Ra₂₂₆(MsTh₁) </span>

<span>α = Alpha decay (release of He Nucleus) </span>
<span>The decay products are meso states that undergo further (β) decay</span>
4 0
3 years ago
What is the energy released in the fission reaction 1 0 n + 235 92 U → 131 53 I + 89 39 Y + 16 1 0 n 0 1 n + 92 235 U → 53 131 I
mihalych1998 [28]

<u>Answer:</u> The energy released in the given nuclear reaction is 94.99 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{53}^{131}\textrm{I}+_{39}^{89}\textrm{Y}+16_{0}^1\textrm{n}

We are given:

Mass of _{92}^{235}\textrm{U} = 235.043924 u

Mass of _{0}^{1}\textrm{n} = 1.008665 u

Mass of _{53}^{131}\textrm{I} = 130.9061246 u

Mass of _{39}^{89}\textrm{Y} = 88.9058483 u u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(m_U+m_{n})-(m_{I}+m_{Y}+16m_{n})\\\\\Delta m=(235.043924+1.008665)-(130.9061246+88.9058483+16(1.008665))=0.1019761u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.1019761u)\times c^2

E=(0.1019761u)\times (931.5MeV)  (Conversion factor:  1u=931.5MeV/c^2  )

E=94.99MeV

Hence, the energy released in the given nuclear reaction is 94.99 MeV.

3 0
3 years ago
Compare the charges and masses of protons, neutrons, and electrons.
Eva8 [605]

Answer:

Explanation:

Protons have a positive charge, with a mass of 1 amu.

Neutrons have no charge, also with a mass of 1 amu.

Electrons have a negative charge, with a mass of 1 amu.

This is why when you're calculating the mass of an element or isotope, we only count the number of protons and neutrons.

3 0
3 years ago
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