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aleksley [76]
3 years ago
10

Please help me!!!!!

Chemistry
1 answer:
kvasek [131]3 years ago
6 0

election circles the nucleus

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Given the following equation: 2 K3N ---> 6 K + N2
Kamila [148]
<span>In a chemical equation, the digits written with each compound show the number of molecules of that compound reacting with other compounds. The reaction consumes and produces compounds in the same proportion as shown by the equation. So, as per given equation 2 moles of K3N will produce 1 mole of N2, hence 12 moles of K3N will produce 6 moles of N2.</span>
3 0
4 years ago
A mixture of hydrocarbons contains 34.8% heptane, C7H16, 10.1% nonane, C9H20, and 55.1% octane, C8H18. The mixture is combusted
Zinaida [17]
<h3>Mass of CO₂ generated from the combustion : 14.277 kg</h3><h3>Further explanation</h3>

Mass Heptane : 0.348 x 17 = 5.916 kg

mass C in Heptane (MW=100.21 g/mol) :

\tt \dfrac{7.12}{100.21}\times 5.916=4.959~kg

Mass Nonane : 0.101 x 17 = 1.717 kg

mass C in Nonane (MW=128.2 g/mol) :

\tt \dfrac{9.12}{128.2}\times 1.717=1.446~kg

Mass Octane : 0.551 x 17 = 9.367 kg

mass C in Otane (MW=114.23 g/mol) :

\tt \dfrac{8.12}{114.23}\times 9.367=7.872~kg

Total mass produced :

4.959+1.446+7.872=14.277 kg

3 0
3 years ago
I am so confused that i don't even understand how to answer it
maksim [4K]

Answer:

What's the question so I can help?

I will just edit my answer when you have asked your question and post it here.

Explanation:

4 0
2 years ago
If you had 20,000 litres of NO2 how many moles would you have
vova2212 [387]

Answer:

The correct answer is 0.89 mol.

Explanation:

At STP (Standard Temperature and Pressure) conditions, 1 mol of an ideal gas occupies a volume of 22.4 L. If we assume STP conditions, we can consider a convertion factor of 1 mol/22.4 L to convert the volume of NO₂ from liters to moles:

20,00 L x 1 mol/22.4 L = 0.89 mol

So, at STP, we would have 0.89 mol of NO₂

6 0
3 years ago
Ill give u brainliest pls help!!<br><br> how is mass of carbon conserved during cellular respiration
Elis [28]

Hi! Glucose and oxygen are required for cellular respiration. As the law of conversation states, in a biochemical reaction, mass is conserved. For every glucose molecule, 6 oxygen molecules are used up and the end products, other than the energy dissipated by the reaction, are 6 water molecules and 6 carbon dioxide molecules. Brainliest?

3 0
3 years ago
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