The process of watering the crops is called irrigation.
Any two methods of irrigation are:
<h3>(i) Sprinkler system:</h3>
This system is used on the uneven land where less water is available. The perpendicular pipes, having rotating nozzles on top, are joined to the main pipeline at regular intervals. Water is allowed to flow through main pipe under pressure, which escapes from the rotating nozzles. In this way water gets sprinkled on the crop.
<h3> (ii) Drip irrigation:</h3>
This system is used to save water as it allows the water to flow drop by drop at the roots of the plants. It is the best technique for watering fruit plants, gardens and trees. Water is not wasted at all.
Answer:
Berilium is located in period 2 group2
Explanation:
you are welcome
Answer:
A planet's <u>hydrosphere</u> can be<u> liquid</u>, <u>vapor</u>, or <u>ice</u>. On Earth, in the places at the <u>north and south pole</u>, water exists in ice or glacier form, in the <u>atmosphere</u> it exists in vapor form and liquid water exists on the <u>surface</u> in the form of oceans, lakes and rivers. It also exists below ground as <u>groundwater</u>, in wells and aquifers. Water collects in clouds, then falls to Earth in the form of <u>rain or snow</u>,
<em>Hope it helps</em>
<em>:D</em>
<em />
Answer:
The correct answer is <em>d. The nucleoside triphosphates have the sugar deoxyribose; ATP has the sugar ribose.</em>
Explanation:
The nucleoside triphosphates are components of DNA (deoxyribonucleic acid) so they are composed by a nitrogenous base (adenine, guanine, thymine or cytosine) and a deoxyribose sugar. In contraposition, ATP (adenosine triphosphate) is composed by the nitrogenous base adenine and a ribose sugar along with three phosphates groups. Unlike ribose, deoxyribose is a 5-carbon sugar which lack of an oxygen atom in C2 position.
Answer:
The initial temperature was 58.4°C
Explanation:
Given the following data:
initial volume = V₁ = 380 mL = 0.38 L
final volume = V₂ = 250 mL = 0.25 L
final temperature = T₂ = -55°C = 218 K
According to Charles's law, the volume of a gas is <em>directly proportional to the temperature</em> (in Kelvin). The mathematical expression is:
V₁/T₁= V₂/T₂
So, we calculate the initial temperature (V₁) as follows:
T₁ = T₂/V₂ x V₁ = 218 K/(0.25 L) x 0.38 L = 331.36 K ≅ 331.4 K
Finally, we convert the initial temperature from K to °C:
T₁= 331.4 K - 273 = 58.4°C