2(5/16)=10/16
2/1=32/16
32/16-10/16=22/16
Answer: 1 6/16 tortes left
Answer:
The greatest common factor of 12m^2 and 9b^4 is 3.
I hope this could help, let me know if you need anymore help.
The inequality would start out looking like this:

Now it's just a matter of solving the inequalities simultaneously. Get rid of the fraction by multiplying everything by 9:

Then distribute the 5 into the parenthesis:

Now add 160 everywhere:

and finally divide everything by 5:
-22<F<266
Answer:
HCF=3
Step-by-step explanation:
Factors of 15t= 3*5*t
Factors of 6s= 2*3*s
HCF= Common factors
common factor = 3
HCF=3
Equation of a parabola with vertex at (2, -1) is
y = a(x - 2)^2 - 1
Using the given point: -3 = a(4 - 2)^2 - 1
-2 = a(2)^2
4a = -2
a = -1/2
Therefore, required equation is
y = -1/2(x - 2)^2 - 1
y = -1/2(x^2 - 4x + 4) - 1
y = -1/2x^2 + 2x - 2 - 1
y = -1/2x^2 + 2x - 3