Answer:
$24.84
Step-by-step explanation:
i did the work lol
give brainliest please
Answer:
The 4 t h term is f(4) = 143
Step-by-step explanation:
<em>Explanation</em>:-
Given function f(1) = -4
Given 'nth' term is f(n) = -3f(n-1) +5
Put n =2 <em> f(2) = -3 f(2-1) +5</em>
= -3 f(1) +5
= -3 (-4) +5
= 12 +5
f(2) = 17
put n= 3
f(n) = -3f(n-1) +5
<em> f(3) = -3 f(3-1) +5</em>
= -3f(2) +5
= -3(17) +5
= -51+5
f(3) = -46
Put n=4
f(n) = -3f(n-1) +5
<em> f(4) = -3f(4-1) +5</em>
<em> f(4) = -3f(3)+5</em>
f(4) = -3(-46)+5
f(4) = 138 +5
f(4) = 143
<u><em>Final answer</em></u>:-
<em>The 4 t h term is f(4) = 143</em>
Answer:
17
Step-by-step explanation:
f(n)=5(n-1)+2
f(4)=5(4-1)+2
=5×3+2
=17
hope it helps
plz. mark as brainliest
Volume of a cone = <span>πr^2(h/3)
r=6
h=27
v = </span><span>π(6^2)27/3
v = </span><span>π (36)(9)
v=</span><span>π324 in. cubed
or
v=1,017.36 in. cubed </span>
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.