For number 4, the midpoint is M, so the lengths of the 2 segments are half of the whole. PM and MQ are 11.

For number 5, TM and MS are 7.5.

Have an amazing day :)

8 0

3 years ago

Chuck's Computer Corporation has 10,000 shares of stock outstanding.

cupoosta [38]

Hi there
the dividend per share of stock
15,000÷10,000
=1.5 per share
if you owned 50 shares
1.5×50
=75

Hope it helps

8 0

4 years ago

Read 2 more answers

You are dealt two cards successfuly without replacement from a shuffled deck of 52 playing card. Find the probability that first

katen-ka-za [31]

The simplified expression is $(\frac{4}{663})$

Step-by-step explanation:

Here, the total number of cards in a given deck = 52

let E : Event of drawing a first card which is King

Total number of kings in the given deck = 4

So, $P(E) = \frac{\textrm{The total number of king}}{\textrm{The total number of cards}}$ = $\frac{4}{52} = (\frac{1}{13} )$

Now, as the picked card is NOT REPLACED,

So, now the total number of cards = 52 - 1 = 51

Total number of queen in the deck is same as before = 13

let K : Event of drawing a second card which is queen

So, $P(K) = \frac{\textrm{The total number of queen}}{\textrm{The total number of cards}}$ = $(\frac{4}{51} )$

Now, the combined probability of picking first card as king and second as queen = P(E) x P(K) = $(\frac{1}{13}) \times(\frac{4}{51}) = (\frac{4}{663} )$