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77julia77 [94]
3 years ago
11

in need of help! Mrs. Sanger blended 8 3/4 gallons of iced tea with some lemonade for a picnic. if there were 13 2/5 gallons of

the beverage, how many gallons of lemonade did she use?​
Mathematics
2 answers:
vodka [1.7K]3 years ago
7 0
13 2/5- 8 3/4= 4 13/20 gallons of lemonade
myrzilka [38]3 years ago
5 0

Answer:

she would of used 4.65 gallons of lemeoade

Step-by-step explanation:

you woupd have to subtracy them

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A fireman, 25.7 m away from a burning building, directs a stream of water from a ground level fire hose at an angle of 47.5° abo
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The coordinates of a particle of water "t" seconds after it leaves the end of the fire hose will be
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Solving for t, we have
.. t = x/(38.4*cos(47.5°)

For x = 25.7 meters, t is about 0.99065 seconds.
Then y will be
.. -4.9*(0.99065)^2 +38.4*sin(47.5°)*0.99065 = 23.238 . . . . meters

The water will hit the building about 23.24 meters above the height of the hose.
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3 years ago
A marble is selected at random from a jar containing 4040 red​ marbles, 5050 yellow​ marbles, and 1010 green marbles. find the t
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The answer will be total green plus total red divided by all existing marbles:
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3 years ago
If the discriminant is negative then the quadratic has
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Answer:

No <em>real</em> solutions (or has two complex roots)

Step-by-step explanation:

The discriminant, <em>b</em>² - 4<em>ac</em>, is the expression (<u><em>radicand </em></u>) of the quadratic equation:

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The value of the discriminant determines the <u>nature</u> and the <u>number of solutions</u> given by the quadratic equation.

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Step-by-step explanation:

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Read 2 more answers
⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden
fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = \frac{354}{1219}

           n = sample of US adults  = 1291

           p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                                    significance level are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ]

                         = [ \frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } , \frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } ]

                         = [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0
3 years ago
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