Answer:
A. 1 rectangle, 2 triangles
B. AB = AE = 5
C. 36.5 square units
Step-by-step explanation:
<h3>A.</h3>
The attached figure shows 1 rectangle (square) and two triangles.
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<h3>B.</h3>
These sides are aligned with the grid, so their length is simply the difference in coordinates along the line:
AB = 2 -(-3) = 5
AE = 3 -(-2) = 5
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<h3>C.</h3>
The area of the square is ...
A = s^2 = 5^2 = 25
The area of triangle BCF is ...
A = 1/2bh = 1/2(3)(5) = 15/2
The area of triangle CDE is ...
A = 1/2bh = 1/2(8)(1) = 4
The total area is the sum of the areas of the square and two triangles:
total area = 25 +7.5 +4 = 36.5 . . . square units
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<em>Additional comment</em>
We note that segment CE divides the figure into <em>trapezoid</em> ABCE and <em>triangle</em> CDE. The trapezoid has bases 5 and 8, and height 5, so its area is ...
A = 1/2(b1 +b2)h = 1/2(5 +8)(5) = 32.5
Triangle CDE has the same area as computed above, 4 square units. So, the total area of the figure is ...
32.5 +4 = 36. 5 . . . . square units
Answer:
98.88
Step-by-step explanation:
I used a calculator and that's what it said the answer is srry if it might be wrong-
<span> $70 / 9 = $7.78
answer
</span><span>$7.78 hourly</span>
Answer:
x = sqroot(122)
Step-by-step explanation:
First find the line that goes thru the middle of the shape. It is the hypotenuse of the bottom/left triangle. Use the pythagorean thm.
9^2 + 5^2 = h^2
81 + 25 = h^2
sqroot106 = h
Now sqroot106 is a leg in the right triangle that is on the top/right in the image.
Use pythagorean thm again.
4^2 + (sqroot106)^2
= x^2
16 + 106 = x^2
122 = x^2
sqroot122 = x