Answer:
it's a rectangle so the area is 6×8=48
The average rate of change for the function f(x) can be calculated from the following equation

By applying the last formula on the given equations
(1) the first function f
from the table f(3π/2) = -2 and f(2π) = 0
∴ The average rate of f =

(2) the second function g(x)
from the graph g(3π/2) = -2 and g(2π) = 0
∴ The average rate of g =

(3) the third function h(x) = 6 sin x +1
∴ h(3π/2) = 6 sin (3π/2) + 1 = 6 *(-1) + 1 = -5
h(2π) = 6 sin (2π) + 1 = 6 * 0 + 1 = 1
∴ The average rate of h =
By comparing the results, The <span>function which has the greatest rate of change is h(x)
</span>
So, the correct answer is option <span>
C) h(x)</span>
Answer:
Table 3
Step-by-step explanation:
The third one.
We have the function
![h(x) = \sqrt[3]{-x+2}](https://tex.z-dn.net/?f=h%28x%29%20%3D%20%5Csqrt%5B3%5D%7B-x%2B2%7D)
Now we will insert values of x in that definition o h(x) and see if the values we obtain match the corresponding y values in the table:
![h(-6) = \sqrt[3]{-(-6)+2}= \sqrt[3]{6+2}= \sqrt[3]{8} = 2\\h(1) = \sqrt[3]{-1+2}= \sqrt[3]{1}= 1\\h(2) = \sqrt[3]{-2+2}= \sqrt[3]{0}= 0\\h(3) = \sqrt[3]{-3+2}= \sqrt[3]{1}= 1\\h(10) = \sqrt[3]{-10+2}= \sqrt[3]{-8}= -2](https://tex.z-dn.net/?f=h%28-6%29%20%3D%20%5Csqrt%5B3%5D%7B-%28-6%29%2B2%7D%3D%20%5Csqrt%5B3%5D%7B6%2B2%7D%3D%20%5Csqrt%5B3%5D%7B8%7D%20%3D%202%5C%5Ch%281%29%20%3D%20%5Csqrt%5B3%5D%7B-1%2B2%7D%3D%20%5Csqrt%5B3%5D%7B1%7D%3D%201%5C%5Ch%282%29%20%3D%20%5Csqrt%5B3%5D%7B-2%2B2%7D%3D%20%5Csqrt%5B3%5D%7B0%7D%3D%200%5C%5Ch%283%29%20%3D%20%5Csqrt%5B3%5D%7B-3%2B2%7D%3D%20%5Csqrt%5B3%5D%7B1%7D%3D%201%5C%5Ch%2810%29%20%3D%20%5Csqrt%5B3%5D%7B-10%2B2%7D%3D%20%5Csqrt%5B3%5D%7B-8%7D%3D%20-2)
We can see that the values match the table 3, so the table 3 represents points on the graph of h(x)
71/20 or 3.55 as a decimal
3 to the third power = 9
2 Open Bracket 64 - (3 x 7) close bracket = 86
9 + 86 = 95