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3 years ago

13

Given the side measurements, classify the triangle as acute, obtuse, right, or not a triangle. 8, 12, 14

1 answer:

ratelena [41]3 years ago

7 0

Answer:

not a triangle because 8,12,14 does not =180

Step-by-step explanation:

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Over [174]

$\huge \mathbb{\green{\fbox{\pink{ANSWER}}}}$

$\\ \: \: \implies \: sin^{4} \: \theta + cos^{4} \: \theta \rightarrow \blue{ \frac{1}{2} }$

$\\ \\ \: \large \mathfrak \green{Solution} :$

$\\ \bf \: Given :$

$\\ \sf \: \: \bf sin \: \theta - cos \: \theta = 0$

$\\ \sf \rightarrow \: sin \: \theta = cos \: \theta$

$\\ \sf \rightarrow \: \frac{sin \: \theta} {cos \: \theta} = 1$

$\\ \sf \rightarrow \: tan \: \theta = 1$

$\\ \sf \rightarrow \: tan \: \theta = tan \: 45 \degree$

$\\ \sf \rightarrow \: \theta = 45 \degree$

$\\ \\ \therefore \: sin^{4} \: \theta + cos^{4} \: \theta$

$\\ \sf \rightarrow \: sin^{4} \: 45 \degree + cos^{4} \: 45 \degree$

$\\ \\\sf \rightarrow \: (\frac{1}{ \sqrt{2} } ) ^{4} +(\frac{1}{ \sqrt{2} } ) ^{4}$

$\\ \sf \rightarrow \: ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}} + ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}}$

$\\ \\\sf \rightarrow \: \frac{1}{2} × \frac{1}{2} + \frac{1}{2}× \frac{1}{2}$

$\\ \\ \sf \rightarrow \: \frac{1}{4} + \frac{1}{4}$

$\\ \\ \sf \rightarrow \: {\cancel \frac{2} {4}}$

$\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \fbox{\pink {\frac{1}{2}}}$

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