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3 years ago

Plz help me well mark brainliest if you are correct!

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

I dont get it :(

Step-by-step explanation:

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Given that f(x) = 2x −5, find the value of x that makes f(x) = 15. (5 points)

vladimir2022 [97]

First you must set f (x) =15:
15 = 2x - 5
Now you must solve like a normal equation:
15 = 2x - 5 )+5
20 = 2*x ):2
10 = x

ANSWER: The value of x is 10

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3 years ago

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Help!!! EASY!!! HELP DUE SOON!!!

Alinara [238K]

4 + 3 + 2 = 9
18/9 = 2

3 x 2 = 6

Answer = 6

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3 years ago

PLEASE HELP ASAP!!

Art [367]

Answer:

See explanation

Step-by-step explanation:

A. P(top)=top outcomes/all kinds of outcomes=4/30=2/15=13.33333333333...%

P(bottom)=bottom outcomes/ all kinds of outcomes=1/30=3.33333333....%

P(side)=25/30=5/6=83.33333333333...%

B. No. If were equally likely, the probabilities for A would have been roughly the same. It seems like the side event is more probable.

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4 years ago

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Ugo [173]

Answer:

Step-by-step explanation:

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3 years ago

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Please someone help me to prove this.

dem82 [27]

<h3>Answer :</h3>

We know that,

$\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}$

$\dag\bf\:sin2A=2sinA\:cosA$

___________________________________

Now, Let's solve !

$\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}$

$\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}$

$\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}$

$\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}$

$\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}$

$\leadsto\:\bf{tan(A+B)}$

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3 years ago

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