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Mamont248 [21]
3 years ago
5

In the figure below, C is between A and D, and B is the midpoint of AC. If AD=20 and BC=6, find CD.

Mathematics
2 answers:
Leokris [45]3 years ago
8 0

Answer:

8

Step-by-step explanation:

AC and BC are the same, so both equal 6

6+6 is 12

Subtract 12 from 20

20-12=8

CD is 8

Vesna [10]3 years ago
8 0
8 i think, sorry if its wrong:) I can give an explanation if needed!
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Round 8.795 to the nearest cent
Tatiana [17]

Answer:

8.80

Step-by-step explanation:

4 0
3 years ago
A supply company manufactures copy machines. The unit cost C (the cost in dollars to make each copy machine) depends on the numb
sergij07 [2.7K]

Answer: \$18,629

Step-by-step explanation:

Given

The unit cost is given by

C(x)=0.6x^2-168x+30,389

find the derivative of the unit cost and equate it to zero to obtain the minimum value

C'(x)=0.6\times 2x-168\\\Rightarrow 0.6\times 2x-168=0\\\Rightarrow 1.2x=168\\\\\Rightarrow x=\dfrac{168}{1.2}\\\\\Rightarrow x=140

Substitute 140 for x in the cost function, we get

C(140)=0.6[140]^2-168(140)+30,389\\C(140)=11,760-23,520+30,389\\C(140)=\$18,629

7 0
2 years ago
Will ran 120 minutes in the past two days. He ran 20 more minutes the second day than the first day. how many minutes did he run
valentinak56 [21]
Here is the equation: x+(x+20) = 120

Since you can't combine anything yet, its x+x+20=120

You need to get x by itself

Minus 20 from both sides

Its x+x=100 now

Combine the x's which is now 2x

Now divide 100 by 2 which is 50

x=50
---------------

Lets check:

50+(50+20)=120

Now combine the numbers in the parentheses

Its now 50+70=120

50+70=120 and 70-50=20

As you can see, he ran 50 minutes the first day and 70 minutes the second day 
4 0
3 years ago
Add or subtract. Write fractions in the simplest form <br> 5) 5.73 – (-3.56) <br> 6) − 5/3 + 2 1/3
Olenka [21]

Answer:

Step-by-step explanation:

5.73 – (-3.56)= 9.29

− 5/3 + 2 1/3= 2/3

4 0
3 years ago
Five students go through the lunch line.Each student pays $1.85 for their lunch and gets 3 cookies.The total amount paid is $20.
erastovalidia [21]

Hello there! The cost of a cookie is $0.72.

Start by multiplying the cost of lunch by 5 and subtract that from the total to get rid of the cost of lunch.

$1.85 x 5 = $9.25

$20 - $9.25 = $10.75

So, there were FIVE students and each bough THREE cookies. To find the cost for each cookie, first divide the total spent on cookies by 5 to get what each student spent on cookies, then by 3 to see how much each cookie cost.

$10.75/5 = $2.15

$2.15/3 = 0.716666667, which can be rounded to $0.72.

I hope this helps and have a great rest of your day!

6 0
3 years ago
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