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uranmaximum [27]
3 years ago
11

Suppose you have three consecutive integers.The greatest of the three integers is twice as great as the sum of the first two.Wha

t are the integers?
Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer:

0, 1, 2

Step-by-step explanation:

So, since there are three consecutive integers, you have the equations

x, x+1, x+2 where x is the smallest number.

The greatest of the three integers= x+2

Finish setting up your equation;

2(x+x+1)=x+2

Combine like terms;

2(2x+1)=x+2

Distribute;

4x+2=x+2

3x=0

x=0

x+1=1

x+2=2

Hope this helps:) Have a good day!

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QUESTION:- DETERMINE THE X-INTERCEPT AND THE Y-INTERCEPT FOR THE GRAPH OF THE EQUATION.

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STANDARD EQUATION:- y=mx+c

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SO GIVEN EQUATION:- 2x - 3y + 36 = 0

WE CAN SOLVE THIS TO CHANGE IN FORMAT OF STANDARD EQUATION

2x - 3y + 36 = 0 \\ 2x + 36 =3y \\ y =  \frac{2}{3} x +  \frac{36}{3}  \\ y =  \frac{2}{3} x +  \frac{ \cancel{36}^{ \:  \: 12} }{ \cancel3}  \\ y =  \frac{2}{3} x +  12 \\

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