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3 years ago

Order the following numbers from least to greatest:

Mathematics

1 answer:

Illusion [34]3 years ago

8 0

Answer:

$\sqrt{5} \\ 2.2 \\ \sqrt{4} \\ \sqrt{2} \\ \sqrt{1}$

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Lesson 4-2

Anon25 [30]

Answer:

-25

Step-by-step explanation:

Given the equation 25 + x =

Subtract 25 from both sides

25 + x - 25 = 0 - 25

x = 0 - 25

x = -25

Hence the blank box will be -25

4 0

3 years ago

What's an equation that the answer would be x= -3?

FromTheMoon [43]

Answer:

there are infinity ♾ equations can have x = -3 as answer plz give more details

Examples :

-9x - 27 = 0

x + 3 =0

2x -1 = - 7

6 0

3 years ago

Read 2 more answers

Using Cramer's rule to solve linear systems.

Rzqust [24]

Answer: Last Option

$x=2,\ y=-5$

Step-by-step explanation:

Cramer's rule says that given a system of equations of two variables x and y then:

$x =\frac{Det(A_X)}{Det(A)}$

$y =\frac{Det(A_Y)}{Det(A)}$

For this problem we know that:

$Det(A) = |A|=\left|\begin{array}{ccc}4&-6\\8&-2\\\end{array}\right|$

Solving we have:

$|A|= 4*(-2) -(-6)*8\\\\|A|=40$

$Det(A_X) = |A_X|=\left|\begin{array}{ccc}38&-6\\26&-2\\\end{array}\right|$

Solving we have:

$|A_X|=38*(-2) - (-6)*26\\\\|A_X|=80$

$Det(A_Y) = |A_Y|=\left|\begin{array}{ccc}4&38\\8&26\\\end{array}\right|$

Solving we have:

$|A_Y|=4*(26) - (38)*8\\\\|A_Y|=-200$

Finally

$x =\frac{|A_X|}{|A|} = \frac{80}{40}\\\\x=2$

$y =\frac{|A_Y|}{|A|} = \frac{-200}{40}\\\\y=-5$

4 0

3 years ago

jake is getting a new phone! he buys the service is $50 per month. write the funtion that would represent on how much jake sends

I am Lyosha [343]

Since x=months,

50x=y

Where x is the number of months times the monthly charge. Y is just the output, or end value.

I hope this helps!
~kaikers

4 0

4 years ago

A car requires 25 litres of petrol for covering a distance of 350 km how much petrol will be required by the car to cover a dist

jasenka [17]

75 litres of petrol would be required

4 0

3 years ago

Read 2 more answers