Answer:
19 1-point shots and 32 2-point shots
Step-by-step explanation:
Let x be the amount of 1-point shots they made and y be the amount of 2-point shots they made then...
x+y=51
x+2y=83
We can solve this equation using elimination. In this case, we can eliminate x be subtracting the two equations.
-y=-32
Divide both sides by -1
y=32
Plug this back into the equation to solve for x
x+32=51
Subtract 32 from both sides
x=19
They scored 19 1-point shots and 32 2-point shots.
Answer:
Step-by-step explanation:
Given the explicit function as
f(n) = 15n+4
The first term of the sequence is at when n= 1
f(1) = 15(1)+4
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 15(2)+4
f(2) = 34
d = 34-19
d = 15
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)15)
S20 = 10(38+19(15))
S20 = 10(38+285)
S20 = 10(323)
S20 = 3230.
Sum of the 20th term is 3230
For the explicit function
f(n) = 4n+15
f(1) = 4(1)+15
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 4(2)+15
f(2) = 23
d = 23-19
d = 4
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)4)
S20 = 10(38+19(4))
S20 = 10(38+76)
S20 = 10(114)
S20 = 1140
Sum of the 20th terms is 1140
Answer: x=-65
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
A or b or c maybe try one of those
The answer might be 2,640 because I multiplied 10 and 264