Answer:
2: 6+4+6= 16
3: 6+6+9+9+18=48
4: 6+2+12+3+8= 36
I really hope this helped I’m not very Experienced in this.
Answer:
We need a sample of size at least 13.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

90% confidence interval: (0.438, 0.642).
The proportion estimate is the halfway point of these two bounds. So

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?
We need a sample of size at least n.
n is found when M = 0.08. So






Rounding up
We need a sample of size at least 13.
1/(1/R1 + 1/R2 + 1/R3)
= 1/ (R2R3 + R1R3 + R1R2)/R1R2R3
= R1R2R3/ (R2R3 + R1R3 + R1R2)
1 quarter= .25
200 × .25= 50
1 dime= .10
.10×15= 15
1 penny= .01
.01× 300= 3
Answer: 50+15+3= $68