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almond37 [142]
3 years ago
14

NEED HELP ASAP. please do not answer if you won’t help. If three resistors with resistances R1,R2,R3, are connected in parallel

their combined resistance R is given by formula R. Will give brainliest if helpful

Mathematics
1 answer:
ANEK [815]3 years ago
3 0
1/(1/R1 + 1/R2 + 1/R3)
= 1/ (R2R3 + R1R3 + R1R2)/R1R2R3
= R1R2R3/ (R2R3 + R1R3 + R1R2)
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I will rate you brainliest
katovenus [111]

Answer:

D. Factoring trinomials

Step-by-step explanation:

The factoring trinomials method is the best way to factor the expression, since it is in the standard trinomial form ax² + bx + c

In this method, you can factor the expression by finding 2 factors of c that add up to b.

The expression is not in the simplest form, and difference of squares cannot be used because there are no perfect squares. Prime factorization is also not used for factoring expressions with variables.

So, D is the right answer.

5 0
3 years ago
Consider circle H with a 6 centimeter radius. If the length of minor arc ST is 11/12 π, what is the measure of ∠RST? Assume RS ≅
Natalka [10]
Check the picture below.

since the arcs of ST and RS are twins, and the circle has a total radians of 2π, then the arcRT is just 2π - arcST - arcRS.

As you can see, arcRT is the "intercepted arc" by the "inscribed angle" RST, thus

\bf \widehat{RT}=2\pi -\widehat{ST}-\widehat{RS}\implies \widehat{RT}=2\pi -\cfrac{11\pi }{12}-\cfrac{11\pi }{12}
\\\\\\
\widehat{RT}=2\pi -\cfrac{22\pi }{12}\implies \widehat{RT}=\cfrac{2\pi }{12}\implies \widehat{RT}=\cfrac{\pi }{6}\\\\
-------------------------------\\\\
\measuredangle RST=\cfrac{\pi }{6}\cdot \cfrac{1}{2}\implies \measuredangle RST=\cfrac{\pi }{12}

3 0
3 years ago
Read 2 more answers
Can someone help with my homework ?
horsena [70]
Let's work backwards. The 2001 team won 29 games. They won 2 more games than the 2000s team, 29-2=27. The 200s team won 27 games. The 2000 team won 27 games, and they won 3 more than the 1999 team. 27-3 = 24.

The 1999 team won 24 games.
8 0
3 years ago
Read 2 more answers
In a geometric series, the first term is 108 and the common ratio is \frac{2}{3}. Find the sum of the first 8 terms.
Valentin [98]

Answer:

311.36

Step-by-step explanation:

For  a geometric series sum of first n terms is a(1-r^n)/(1-r)

if r is less than 1.

where a is the first term and r is the common ratio.

____________________________\

given

a = 108

r = \frac{2}{3}.

n = 8

thus , sum of n term is

a(1-r^n)/(1-r)\\=>108(1-(2/3)^8)/(1-2/3)\\=> 108 (1 - 256/6561)/1/3\\=> 108(6561-256)/ 6561/1/3\\=> 108(6305)/2187\\=>311.36

Thus sum of first 8 terms is 311.36

7 0
3 years ago
Estimate the sum of the decimals below by rounding each summand to the
xeze [42]

Answer:

it would be rounded to 9 as the nearest whole number (the number in decimal form is 9.304 when added up to get the sum)

6 0
3 years ago
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