<span>A polynomial with the given zeros can be represented as
f(x) = (x-1)(x-2)(x+2)(x+3).
Note that if you set f(x) = 0, then 1,2,-2, and -3 certainly are the solutions. From here, we simply multiply/expand out the polynomial. We can do this in a variety of ways, one of which is taking the left two and right two products separately. We have
(x-1)(x-2) = x^2 - 3x + 2
and
(x+2)(x+3) = x^2 + 5x + 6.
This gives that
f(x) = (x^2 - 3x + 2) (x^2 + 5x + 6).
Expanding this expression out then gives us our answer as
f(x) = x^4 + 2x^3 - 7x^2 - 8x + 12
or answer choice B.</span>
The factoring method which can be considered for such a cubic tetranomial expression is; factor by grouping sum of cubes.
<h3>What factoring method can be considered for the polynomial?</h3>
It follows from the task content that the order of the Polynomial is 3 and the polynomial is a tetranomial as it contains 4 terms.
On this note, since 3x³ is not a perfect cube, it follows that the best factorisation method for such a polynomial is; factor by grouping sum of cubes.
Read more on factorisation;
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Answer:#1. 13, 18, 23, 28, 33, 38, 4, 48, 53
To generate the next term, add 5 to the previous term.
Step-by-step explanation:18-13=5 see if it is the same for the others and go from there.
She is incorrect because 14 multiplied by 2 equals 28, which means she wouldn’t have any money left over.
Answer:
39
Step-by-step explanation:
g(x)= -2x+2 and f(x)= 3x^2+4
(g+f)(-3)
g(-3) = -2(-3) +2 = 6+2 =8
f(-3) = 3 (-3)^2 +4 = 3(9)+4 = 27+4 = 31
(g+f)(-3) = g(-3) + f(-3) = 8+31 = 39
