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uysha [10]
2 years ago
11

If the points (1, -4) and (-1, r) and lie on a line whose slope is 5, what does r equal?

Mathematics
1 answer:
Alja [10]2 years ago
3 0

Answer:

mabe 5

Step-by-step explanation

becuse its probly in the x1,5 becuse it slopes down 5

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Use the table for 19-23. write each ratio in the form a/b and then as a decimal. Tell whether each decimal is a terminating or r
stellarik [79]
All you are basically doing is making ratios.
Basketball to football would be 5 to 11 or 5:11 or 5/11.
What you do is in the order you said it (basketball to football) you find that info and make it a ratio. A ratio must be simplified and can be written 3 ways, as shown above.

Hockey to lacrosse would be 6 to 10 and simplified would be 3 to 5.

Try doing 3 and 4 and 5 on your own to help you understand it more:) if you have any questions tell me.
4 0
3 years ago
Read 2 more answers
If f(x) = 2x^2 - 5 and g(x) = 3x3, find (f-g)(x).
77julia77 [94]

\text{Given that,}~ f(x) = 2x^2 -5 ~ \text{and}~ g(x) = 3x^3\\\\\text{Now,}\\\\ ~~(f-g)(x)\\\\=f(x) - g(x)\\\\=2x^2 -5 - 3x^3\\\\=-3x^3 +2x^2 -5

4 0
2 years ago
Find the distance between the pair of points (-7, 2) and (-2, 14)
VladimirAG [237]

Step-by-step explanation:

Distance between points (-7, 2) and (-2, 14) is 13

6 0
3 years ago
Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
Solve the inequality. -45<-9k would the answer be 5>k or 5
Mashutka [201]

Answer:

5 > k

Step-by-step explanation:

-45 < -9k

Switch sides

-9k > -45

Multiply both sides by -1 (reverse the inequality)

( -9k )( -1 ) < ( -45 )( -1 )

Simplify

9k < 45

Divide both sides by 9

9k/9 < 45/9

Simplify

K < 5


8 0
2 years ago
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