The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches

So, length of sides will be,

<span>5x-4+6<16
Subtract 6 from both sides
5x-4<10
Add 4 to both sides
5x<14
Divide 5 on both sides so that the only thing remaining on the left side is the variable x.
Final Answer: 14/5 or 2 4/5 or 2.8 *All answers are equivalent to each other.</span>
Answer:
52° is correct answer of this question
hope it helps
thanks for free points
Answer:

Step-by-step explanation:





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Answer:
A. -19
Step-by-step explanation:
5x - 3y - z
5 (-2) - 3 (2) - 3
-10 - 6 - 3
-16 - 3
-19