1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vesna [10]
2 years ago
9

Could a polyhedron exist with the given number of faces, vertices, and edges? Drag yes or no to each combination

Mathematics
2 answers:
Bogdan [553]2 years ago
7 0

Answer:

no

NO

NO

Step-by-step explanation:

good luck have a nice day

DanielleElmas [232]2 years ago
5 0

Answer:

(a) No

(b) No

(c) No

Step-by-step explanation:

Given

See attachment

Required

Select Yes or No for each

To do this, we make use of Euler's formula

F + V - E = 2

Where

F \to Faces; V \to Vertices; E \to Edges

(a):\ Faces = 8; Vertices = 12; Edges = 6

Using: F + V - E = 2

8 + 12 - 6 = 2

14 = 2

<em>The above equality is false. Hence, (a) does not exist</em>

(b):\ Faces = 6; Vertices = 6; Edges = 4

Using: F + V - E = 2

6 + 6 - 4 = 2

8 = 2

<em>The above equality is false. Hence, (b) does not exist</em>

<em />

<em />(c):\ Faces = 20; Vertices = 30; Edges = 12<em />

Using: F + V - E = 2

20 + 30 - 12 = 2

38 = 2

<em>The above equality is false. Hence, (c) does not exist</em>

You might be interested in
Find the number that makes the 2 fractions equivalent 3/8=9/?
Lorico [155]

Answer:

24

Step-by-step explanation:

The numerator of the equivalent fraction of 3/8 is 9. From this, we can see that the common factor that is being multiplied is 3. So the denominator, 8, has to be multiplied by 3 as well which gives you 24. 9/24 is an equivalent fraction of 3/8

6 0
3 years ago
Read 2 more answers
Find the missing angle.
Alina [70]

Answer:

sorry bro just wanted the points but thanks have a great day

Step-by-step explanation:

3 0
3 years ago
Enter the decimal represented by the shaded square.<br> The shaded square represents
dlinn [17]

Answer: the shaded squares are equal to 0.3

5 0
2 years ago
Quenstions below/screenshot
Llana [10]

Answer:

Question 2: Radios remaining is the dependent variables and the hours are the Independent variables

5 0
2 years ago
What is continuous​ compounding? how does the apy for continuous compounding compare to the apy​ for, say, daily​ compounding? e
aliya0001 [1]
Continuous compounding is the mathematical limit that compound interest can reach.

It is the limit of the function A(1 + 1/n) ^ n as n approaches infinity. IN theory interest is added to the initial amount A  every infinitesimally small  instant.
The limit  of (1 + 1/n)^n is the number e ( = 2.718281828 to 9 dec places).

Say we invest  $1000  at daily compounding at yearly interest of 2 %. After 1 year the $1000 will increase to:-

1000 ( 1 + 0.02/365)^365 = $1020.20

with continuous compounding this will be 

1000 * e^1  =  $2718.28  
4 0
3 years ago
Read 2 more answers
Other questions:
  • 06.01) Saturday morning there were 7 adults and 20 kids at Pump and Jump Land. The morning cash registers show $236 was collecte
    9·2 answers
  • Find the value of x.
    7·1 answer
  • Solve for the smallest value of $x$ such that $24x^2 + 17x - 20 = 0.$ Express your answer as a simplified common fraction.
    14·1 answer
  • Solve for f in the proportion.<br> 28/44 = F/99 F = ?
    14·1 answer
  • What is the sum of the following equatiioin? 10x+20y+5x=?
    13·2 answers
  • Example 4
    13·1 answer
  • A can of paint is a right circular cylinder. The radius of the base is 5 centimeters and the height is 12 centimeters. Find the
    12·2 answers
  • Jon invests $4,100 into an account that pays 5 percent simple interest each year. What is the total balance in the account after
    13·2 answers
  • Simplify (4y - 3x - 2) - (7y + 4x + 3)
    11·2 answers
  • angelo's mother put $50 on a lunch card he spends the same amount each day for lunch. what is the constant rate of change for th
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!