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Vladimir [108]
4 years ago
5

Difference of a number and -3 is 6. what is the number

Mathematics
1 answer:
tiny-mole [99]4 years ago
5 0
Let x = the number we are looking for:

Difference means that we subtract:

x-(-3)=6

Two negative signs turn it into one positive sign (a plus):

x+3=6

We need to get x by itself, so we subtract 3 from both sides:

x=3

So now we know that the number we were asked to find is 3.
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A cylinder has a radius of 5 and height of 3. what is the volume
Ratling [72]

Answer: Volume of the cylinder is 75π or 235.62 cm³

                    Volume of cylinder =πr²h

                                        where r is radius and h is height.

Here given radius = 5 and height = 3

Using the formula: πr²h

                              : π * 5² * 3

                              : π * 5 * 5 * 3

                              : 75π or 235.62 cm³

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3 years ago
Let y = (2 6) and u = (7 1). Write y as the sum of a vector in Span(u) and a vector orthogonal to .
Minchanka [31]

The question is missing. Here is the complete question.

Let y = \left[\begin{array}{ccc}2\\6\end{array}\right] and u = \left[\begin{array}{ccc}7\\1\end{array}\right]. Write y as the sum of a vector in Span(u) and a vector orthogonal to u.

Answer: y = \left[\begin{array}{ccc}\frac{21}{10} \\ \frac{3}{10} \end{array}\right] + \left[\begin{array}{ccc}\frac{-1}{10}\\ \frac{57}{10} \end{array}\right]

Step-by-step explanation: The sum of vectors is given by

y =  y_{1} + z

where  y_{1} is in Span(u);

vector z is orthogonal to it;

First you have to compute the orthogonal projection y_{1} of y:

y_{1} = proj y = \frac{y.u}{u.u}.u

Calculating orthogonal projection:

\left[\begin{array}{c}2\\6\end{array}\right].\left[\begin{array}{c}7\\1\end{array}\right] = \left[\begin{array}{c}9\\6\end{array}\right]

\left[\begin{array}{c}7\\1\end{array}\right].\left[\begin{array}{c}7\\1\end{array}\right] = \left[\begin{array}{c}49\\1\end{array}\right]

y_{1} = \frac{9+6}{49+1}.u

y_{1} = \frac{15}{50}.u

y_{1} = \frac{3}{10}.u

y_{1} = \frac{3}{10}.\left[\begin{array}{c}7\\1\end{array}\right]

y_{1} = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]

Calculating vector z:

z = y - y_{1}

z = \left[\begin{array}{c}2\\6\end{array}\right] - \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]

z = \left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]

Writing y as the sum:

y = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right] + \left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]

5 0
3 years ago
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