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4 years ago

15

5^-2 written as a positive exponent

1 answer:

azamat4 years ago

5 0

1/25 is the positive exponent of 5^-2

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What is the quotient? 57,263/28

Juliette [100K]

Step-by-step explanation:

R= 2,045.1071428571 espero sea lo que necesitas :)

3 0

3 years ago

3. At the mission museum Mrs. Perez visited over break, there is a pond like the one below that has a ring-shaped sidewalk aroun

yarga [219]

Answer:

(a) $36\pi \ m^2$

(b) $113.04\ m^2$

Step-by-step explanation:

(a) Write and simplify an expression for the exact area of the sidewalk.

(b) Find the approximate area of the sidewalk. Use 3.14 to approximate .

(a) The sidewalk area is the difference in the area of outer circle and inner circle.

Use formula $A=\pi r^2$ for the area of the circle:

$A_{outer}=\pi \cdot 10^2=100\pi \ m^2\\ \\A_{inner}=\pi \cdot 8^2=64\pi \ m^2$

The difference is

$A_{Sidewalk}=A_{outer}-A_{inner}=100\pi -64\pi =36\pi \ m^2$

(b) Use approximation $\pi \approx 3.14,$ then

$A_{Sidewalk}\approx 36\cdot 3.14=113.04\ m^2$

4 0

3 years ago

Simplify the expression and find its value when a = 5 and b = -3 .

kenny6666 [7]

Answer:

$\sf\longmapsto \: 38$

Step by step explanation:

$\sf\longmapsto \: 2a² + 2ab +3-ab$

$\sf\longmapsto \: 2a² + 3 + ab (2-1)$

$\sf\longmapsto \: 2a² + 3 + ab (1)$

$\sf\longmapsto \: 2a² + 3 + ab$

$\sf\longmapsto \: 2a² + ab + 3$

Putting a = 5 b = - 3

$\sf\longmapsto \: 2(5) {}^{2} + (5) (-3) +3$

$\sf\longmapsto \: 2 (25) - 15 + 3$

$\sf\longmapsto \: 50 - 12$

$\sf\longmapsto \: 38$

7 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!!!!! HELP FAST! ASAP!

denpristay [2]

I don't know which form you want but here

Exact form: 5/4

decimal form is: 1.25

mixed number form:

1 1/4

8 0

3 years ago

The measure of central angle ABC is radians.

mezya [45]

Answer:

$9\pi\ units^{2}$

Step-by-step explanation:

we know that

The measure of central angle ABC is $\frac{\pi}{2}$ radians

so

$\frac{\pi}{2}=90\°$

$360\°$ subtends the complete circle

The area of the shaded sector is the area of a quarter circle

so

The area of a quarter circle is equal to

$A=\frac{1}{4}\pi r^{2}$

we have

$r=6\ units$

substitute

$A=\frac{1}{4}\pi (6)^{2}=9\pi\ units^{2}$

5 0

4 years ago