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gulaghasi [49]
3 years ago
11

2x+6=3x+4 Write a real-world problem that can be represented by the given equation. Explain what your variable represents.

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0

Here, we are required to write a real-world problem that can be represented by the given equation

On the left hand side of the equation, we can say that :

The addition of 6 to twice my cousin's age which gives 2x+6.

On the right hand side, we can say the addition of 4 to thrice my cousin's age which also gives:

3x +4

Ultimately, the real-world problem may be in the form :

Six added to Twice my cousin's age is equal to 4 added to thrice his age.

Also, my variable, x represents my cousin's age.

Read more:

brainly.com/question/12184348

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Over [174]
\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right) \ \textgreater \  \ln \left(6^x\right)=\ln \left(21\right)

\mathrm{Apply\:log\:rule}:\ \log _a\left(x^b\right)=b\cdot \log _a\left(x\right) \ \textgreater \  \ln \left(6^x\right)=x\ln \left(6\right)

x\ln \left(6\right)=\ln \left(21\right) \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}\ln \left(6\right) \ \textgreater \  \frac{x\ln \left(6\right)}{\ln \left(6\right)}=\frac{\ln \left(21\right)}{\ln \left(6\right)}

Therefore \: x=\frac{\ln \left(21\right)}{\ln \left(6\right)}

In your case ln means \frac{log 21}{log 6}
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