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Goryan [66]
3 years ago
12

4. Acertijo.

Mathematics
1 answer:
7nadin3 [17]3 years ago
3 0

Las edades de cada uno de los integrantes del acertijo son:

  • Luisa = 3 años
  • Juan = 6 años
  • Carmen = 8 años

Cálculo por medio de ecuaciones.

Para identificar la edad de cada persona en el acertijo, se pueden crear ecuaciones con la información brindada, aunque, primero se deben asignar variables:

  • <em>L = Edad de Luisa</em>
  • <em>J = Edad de Juan</em>
  • <em>C = Edad de Carmen</em>

Teniendo estas variables se procede a crear las ecuaciones, la primera parte del ejercicio dice que "<em>Luisa es 3 años más joven que su hermano Juan</em>", entonces la ecuación podría ser:

  • 1. J = L + 3

La segunda parte dice que "<em>su hermana Carmen es 2 años mayor que Juan</em>", entonces:

  • 2. C = J + 2

Y la tercera parte menciona que "<em>Juan tiene el doble de edad que Luisa</em>", por lo tanto:

  • 3. J = 2L

Se realiza el método de reducción con la primera y la tercera ecuación, para calcular el valor de L:

  • 1. J = L + 3 (<em>Se multiplica por (-1) puesto que la variable que se busca reducir es J</em>)
  • 3. J = 2L

Entonces se calcula:

  • - J = - L - 3
  •  J = 2L

 

  • 0 = L - 3 (<em>El número 3 que está restando se pasa a sumar al otro lado de la igualdad</em>)
  • 3 = L
  • <u>L = 3</u>

Teniendo el valor de L, se calcula el valor de J con la tercera ecuación:

  • J = 2L
  • J = 2 * 3
  • <u>J = 6</u>

Y con el valor de J, se calcula el valor de C con la segunda ecuación:

  • C = J + 2
  • C = 6 + 2
  • <u>C = 8</u>

De esta forma, se calcula que <u>las edades de Luisa, Juan y Carmen son: 3 años, 6 años y 8 años respectivamente</u>.

Más información:

brainly.com/question/1225667?referrer=searchResults

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