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shutvik [7]
3 years ago
15

Inverse of g(x) = x^2+1

Mathematics
1 answer:
timurjin [86]3 years ago
8 0

To find the inverse, interchange the variables and solve for y

G^-1 (x) = square root x - 1, - square root x-1

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Which of the following is an extraneous solution of sqrt 4x + 41 = x+5
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Answer:

x=-8

Step-by-step explanation:

\sqrt{4x+41}=x+5

on squaring both sides

4x+41=(x+5)^2\\\\4x+41=x^2+10x+25\\\\x^2+6x-16=0\\\\x^2+8x-2x-16=0\\\\x(x+8)-2(x+8)=0\\\\(x-2)(x+8)=0

either x-2=0  or  x+8=0

either x=2 or x=-8

Putting x=2 in original equation, we get

\sqrt{4\times 2+41}=2+5

7=7 hence, it is not an extraneous solution

Putting x=-8 in original equation

\sqrt{4\times (-8)+41}=-8+5

i.e. 3=-3

Hence, x=-8 is an extraneous solution (since it doesn't satisfy the original equation)

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3 years ago
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Answer:

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Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

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The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

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Step-by-step explanation: hoped I helped

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