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uranmaximum [27]
3 years ago
8

Find the sum of the arithmetic sequence 1,3,5,7, .. , 99.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

Look at picture answer is 2500

Step-by-step explanation:

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Please help. 20 points and brainliest.
julia-pushkina [17]

Answer:

minimum -45, maximum 32

Step-by-step explanation:

C=4x-3y

x≥0, y≥4, x+y≤15

Maximum value of C can be achieved at max x and min y

  • min y=4 => max x=15-4=11
  • C=4*11-3*4= 32

Minimum value of C can be achieved at min x and max y

  • min x=0, max y =15
  • C=4*0-3*15= -45

So answer is minimum -45, maximum 32

7 0
3 years ago
Write an equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the l
mamaluj [8]

The equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5 is y = \frac{3}{4}x - \frac{5}{4}

<em><u>Solution:</u></em>

<em><u>The slope intercept form is given as:</u></em>

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5

Given line is perpendicular to  − 4 x − 3 y  =  − 5

− 4 x − 3 y  =  − 5

-3y = 4x - 5

3y = -4x + 5

y = \frac{-4x}{3} + \frac{5}{3}

On comparing the above equation with eqn 1, we get,

m = \frac{-4}{3}

We know that product of slope of a line and slope of line perpendicular to it is -1

\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope m = \frac{3}{4}

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}

\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}

y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}

Thus the required equation of line is found

8 0
3 years ago
The weights of a large number of miniature poodles are approximately normally distributed with a mean of 8 kilograms and a stand
harina [27]

Answer and Step-by-step explanation:

Considering the table attached.

(a) over 9.5 kg;

μ = 8

σ = 0.9

z = 9.5 - 8/0.9 ≈ 1.67

P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475

(b) at most 8.6 kg;

z = 8.6-8/0.9 ≈ 0.67

P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486

(c) between 7.3 and 9.1 kg.

z₁ = 7.3-8/0.9 ≈ -0.78

z₂ = 9.1 - 8/0.9 ≈ 1.22

P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711

3 0
3 years ago
Write the inequality!! Connie’s dog Fido weighs 35 pounds. Her vet placed Fido on a diet. What inequality can you write to find
Butoxors [25]

Answer:   \frac{35-28}{x} \leq 6

Step-by-step explanation:

Let x be the average number of pounds Fido must loss.

Since, the initial weight of Fido is 35 pounds.

And, After losing the weight, the new weight of Fido in pounds = 28 pounds.

Then the time taken for losing the weight

= \frac{\text{ The weight it losses}}{\text{ Average of losing weight per month}}

= \frac{35-28}{x}

According to the question,  it must lose weight within 6 months,

Thus,   \frac{35-28}{x}\leq 6

Which is the required inequality to find the average number of pounds per month.

By solving it we, get,    x\geq \frac{7}{6}

6 0
3 years ago
Which subset(s) of numbers does 8 2/3<br> belong to?
Tems11 [23]

Answer:

Rational number/integer

7 0
3 years ago
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