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2 years ago

Can someone please explain this.

Mathematics

2 answers:

pantera1 [17]2 years ago

7 0

Answer:

XY ║ KL

Step-by-step explanation:

As per details in the diagram, the points K, L and J are midpoints of sides.

KL, KJ and KJ are midsegments.

According to definition of midsegment, XY and KL are parallel.

labwork [276]2 years ago

5 0

Answer:

segment KL

Step-by-step explanation:

There is a theorem in geometry that deals with problem's question.

Theorem:

In a triangle, a segment whose endpoints are midpoints of two sides is parallel to and half the length of the third side.

In this triangle, you are shown that each side is made up of two congruent segments. That makes points J, L, and K midpoints of the three sides of the triangle.

Look at midpoints L and K. They are midpoints of sides YZ and XZ. Join them with segment KL. That segment is parallel to the third side of the triangle, side XY, and half of its length.

Answer: segment KL

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3 years ago

Complete the square to write the quadratic expression in vertex form.

Anvisha [2.4K]

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1. (x - 3)² = 8

2. (x + 2)² = 3

3. (x + 6)² = $\frac{101}{2}$

4. (x + 3)² = 27

5. (x + 4)² = 13

6. $\bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9}$

Step-by-step explanation:

Completion of Square: $(x - a) ^2 = x^2 - 2ax + a^2$

In the following problems the terms in the RHS of the above equation may be missing. We balance the equation. Simplify it and re write it in terms of LHS.

1. x² - 6x + 1 = 0

Taking the constant term to the other side, we get:

x² - 6x = - 1

⇒ x² - 2(3)x = -1

⇒ x² -2(3)x + 9 = - 1 + 9 [Adding 9 to both the sides]

⇒ x² -2(3)x + 3² = 8

⇒ (x - 3)² = 8 is the answer.

2. 3x² + 12x + 3 = 0

Note that the co-effecient of x² is not 1. We make it 1, by dividing the whole equation by 3. And then proceed like the previous problem.

3x² + 12x = -3

Dividing by 3 through out, x² + 4x = - 1

⇒ x² + 2(2) + 4 = -1 + 4

⇒ x² +2(2) + 2² = 3

⇒ (x + 2)² = 3 is the answer.

3. 2x² + 24x = 29

x² + 12x = $\frac{29}{2}$

⇒ x² + 2(6)x + 36 = $\frac{29}{2}$ + 36

⇒ x² + 2(6)x + 6² = $\frac{29 + 72}{2}$

⇒ (x + 6)² = $\frac{101}{2}$ is the answer.

4. x² + 6x - 18 = 0

x² + 6x = 18

⇒ x² + 2(3)x = 18

⇒ x² + 2(3)x + 9 = 18 + 9

⇒ x² + 2(3)x + 3² = 27

⇒ (x + 3)² = 27 is the answer.

5. x² + 8x + 3 = 0

x² + 8x = -3

⇒ x² + 2(4)x = -3

⇒ x² + 2(4)x + 16 = - 3 + 16

⇒ x² + 2(4)x + 16 = 13

⇒ (x + 4)² = 13 is the answer.

6. 9x² - 30x + 6 = 0

9x² - 30x = - 6

⇒ x² $- \frac{30}{9}$ x = - 6

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$\implies x^2 - 2\bigg( \frac{15}{9} \bigg ) x + \bigg ( \frac{15}{9} \bigg ) ^2 = \frac{261}{81}$

$\bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9}$ is the answer.

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