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3 years ago

Group the terms with the variable on one side of the equal sign and simplify. Do not solve. -5t-14=3t

Mathematics

1 answer:

Verdich [7]3 years ago

7 0

Answer:

-14=8x

Step-by-step

-14=3x+5x

-14=8x

If you want the answer for the equation:

-14/8=x

-7/4=x

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At a used dealership, let X be an independent variable representing the age in years of a motorcycle and Y be the dependent vari

GarryVolchara [31]

Answer:

a) Selling price y= a + b (age x)

a= 728.025

b= -38.217

Selling price y = 728.025 - 38.217 age x

SSE=8280.25

Step-by-step explanation:

The regression model can be written as

y=a+bx

Here y=selling price and x is age.

So, the regression model will be

Selling price y= a + b (age x)

We have to find the values of "a" and "b"

$b=\frac{nsumxy-(sumx)(sumy)}{nsumx^{2} -(sumx)^2}$

sumx=5+10+12+14+15=56

sumy=500+400+300+200+100=1500

sumxy=5*500+10*400+12*300+14*200+15*100=14400

sumx²=5²+10²+12²+14²+15²=690

n=5

$b=\frac{5(14400)-(56)(1500)}{5(690) -(56)^2}$

b=-12000/314

b=-38.217

ybar=a+bxbar

a=ybar-bxbar

ybar=sumy/n=1500/5=300

xbar=sumx/n=56/5=11.2

a=300-(-38.217)(11.2)

a=300+428.025

a=728.025

Selling price y = a - b(age x)

Selling price y = 728.025 - 38.217 age x

SSE known as sum of square of error can be calculated as

SSE=sum(y-yhat)²

y 500 400 300 200 100

x 5 10 12 14 15

yhat= 728.025 - 38.217 age x 536.940 345.855 269.421 192.987 154.770

y-yhat -36.940 54.145 30.579 7.013 -54.770

(y-yhat)² 1364.56 2931.68 935.08 49.18 2999.75

SSE=sum(y-yhat)²

SSE=1364.56 +2931.68 +935.08 +49.18 +2999.75

SSE =8280.25

4 0

3 years ago

Write an equation in a slope-intercept form for the line described.

Snezhnost [94]

Answer: y= 4x + 4

Step-by-step explanation: The equation is in slope intercept form, y=mx+b. The slope is the same since it is parallel to the equation, and since b is the x interecept, b is 4.

8 0

4 years ago

The vertices of the trapezoid are J(4m, 4n), K(4q, 4n), M(4p, 0), and L(0, 0). Find the midpoint of the midsegment of the trapez

Lilit [14]

To get the midsegment, namely HN, well, we need H and N

hmm so.... notice the picture you have there, is just an "isosceles trapezoid", namely, it has two equal sides, the left and right one, namely JL and KM

the midpoint of JL is H and the midpoint of KM is N

thus

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square}}\quad ,&{{ \square}})\quad 
% (c,d)
&({{ \square}}\quad ,&{{ \square}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\\\\
-----------------------------\\\\$

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
J&({{ 4m}}\quad ,&{{ 4n}})\quad 
% (c,d)
L&({{ 0}}\quad ,&{{ 0}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{0+4m}{2}\quad ,\quad \cfrac{0+4n}{2} \right)
\\\\\\
\left( \cfrac{4m}{2},\cfrac{4n}{2} \right)\implies \boxed{(2m,2n)\impliedby H}\\\\
-----------------------------\\\\$

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
K&({{ 4q}}\quad ,&{{ 4n}})\quad 
% (c,d)
M&({{ 4p}}\quad ,&{{ 0}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{4p+4q}{2}\quad ,\quad \cfrac{0+4n}{2} \right)
\\\\\\
\left( \cfrac{2(2p+2q)}{2},\cfrac{4n}{2} \right)\implies \boxed{[(2p+2q), 2n]\impliedby N}\\\\
-----------------------------\\\\$

$\bf \textit{so, the midpoint of HN is }
\\\\\\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
H&({{ 2m}}\quad ,&{{ 2n}})\quad 
% (c,d)
N&({{ 2p+2q}}\quad ,&{{ 2n}})
\end{array}\\\\\\
% coordinates of midpoint 
\left(\cfrac{(2p+2q)+2m}{2}\quad ,\quad \cfrac{2n+2n}{2} \right)
\\\\\\
\left( \cfrac{2(p+q+m)}{2},\cfrac{4n}{2} \right)\implies (p+q+m)\quad ,\quad 2n$

5 0

3 years ago

Read 2 more answers

What is the answer?????????

jarptica [38.1K]

Divide 4,856 by by 16

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3 years ago

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A car rental agency advertised renting a car for $24.95 per day and $0.28 per mile. If Greg rents this car for 3 days, how many

kirza4 [7]

Answer/Step-by-step explanation: