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2 years ago

Mandy is on a bus that is traveling at a constant speed of 60 minutes per hour how far will she travel in 3.5 hours

Mathematics

1 answer:

Nataly_w [17]2 years ago

7 0

Answer:

The answer for ur problem is 17 1/7

Step-by-step explanation:

60 ÷ 3.5 = 17 1/7

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Two terms of an arithmetic sequence are a10=16 and a35=66 find the sum of the first 75 terms

andrew11 [14]

The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.

<h3>How to find the sum of terms using Arithmetic sequence formula</h3>

aₙ = a + (n - 1)d

where

a = first term

d = common difference

n = number of terms

Therefore, let's find a and d

a₁₀ = a + (10 - 1)d

a₃₅ = a + (35 - 1)d

Hence,

16 = a + 9d

66 = a + 34d

25d = 50

d = 50 / 25

d = 2

16 - 9(2) = a

a = 16 - 18

a = -2

Therefore, let's find the sum of 75 terms of the arithmetic sequence

Sₙ = n / 2 (2a + (n - 1)d)

S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)

S₇₅ = 37.5 (-4 + 148)

S₇₅ = 37.5(144)

S₇₅ = 5400

learn more on arithmetic sequence here: brainly.com/question/1687271

4 0

2 years ago

-2x-y=-9<br> 5x-2y=18<br> substitution

KIM [24]

$-2x-y=-9 \\
5x-2y=18 \\ \\
\hbox{solve the first equation for y:} \\
-2x-y=-9 \ \ \ |+2x \\
-y=-9+2x \ \ \ |\times (-1) \\
y=9-2x \\ \\
\hbox{substitute 9-2x for y in the second equation:} \\
5x-2(9-2x)=18 \\
5x-18+4x=18 \\
9x-18=18 \ \ \ |\div 9 \\
x-2=2 \ \ \ |+2 \\
x=4 \\ \\
y=9-2x=9-2 \times 4=9-8=1 \\ \\
\boxed{(x,y)=(4,1)}$

6 0

2 years ago

Read 2 more answers

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

4 0

3 years ago

Factor: m^2 - 20m - 21

Ganezh [65]

(m-21) (m+1)there I thinks it's right unless I messed up my work

6 0

3 years ago

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The sequence an = one third(3)n − 1 is graphed below: coordinate plane showing the points 2, 1; 3, 3; and 4, 9 Find the average

Maru [420]

The given sequence is:

$a(n)= \frac{1}{3} (3)^{n-1}$

a(2)=1
a(3)=3
a(4)=9

We are to find the average rate of change between n=3 and n=4 for the given function.

Average rate of change = $\frac{a(4)-a(3)}{4-3} = \frac{9-3}{1}=6$

So the average rate of change for the given function from n = 3 to n = 4 is 6

8 0

3 years ago

Read 2 more answers