x=18 i got this because i saw that 11 is 8 more than 3 soo i added 8 to 10 and i got 18
set f(x) equal to y
y = 19/ x^3
swap x and y
x = 19/y^3
make y the subject
xy^3 = 19
y^3 = 19/x
![y = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
then just replace y with f^-1(x)
![f(x) = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
hope this helped! have a good day ~ •lipika•
Answer:
oh its really easy
so for -7 you would just count up but negatives so -7 and -5= -13 :)
Step-by-step explanation:
Answer:
p = 26
Q = 79
R =75
Step-by-step explanation:
because MNO is same as PQR (direction wise)
Do 45/225 and simplify and that’s your answer
