Find the distance between (5,2) and (5,38)

Analyze the diagram below and complete the statement that follows.

zzz [600]

Answer:

A: 42

Step-by-step explanation: 10.5x4=42

4 0

3 years ago

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An unprepared student makes random guesses for the ten true-false questions on a quiz. Find the probability that there is at le

hoa [83]

Answer:

0.999

Step-by-step explanation:

At least 1 correct means, 1 correct, 2 correct, 3 correct ... until 10 correct. That would be a long process to calculate.

Instead we use the complement rule to calculate.

$P(x\geq1)=1-P(x$

So we need to find P(x<1). So this is getting 0 answers correct, or 10 incorrect.

In true false question, probablity of correct is 1/2 and incorrect is 1/2, hence,

Probability of 10 incorrect is (1/2)^10

Thus,

$P(x\geq1)=1-(\frac{1}{2})^{10}=0.999$

So the answer is 0.999 (rounded to nearest thousandth)

3 0

3 years ago

Create a scenario for the following equation: 3x+0

bulgar [2K]

There is no entrance fee for an amusement park however you need to pay 3$ to ride the rides

3 0

3 years ago

In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T

dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + $\frac{h^{2} }{2!}$ f''(a) = 0

$h = \frac{-f'(a) }{f''(a)}$ ± $\frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}$

So, we get the succeeding equation for Newton's method as

$x_{i+1} = x_{i} + \frac{1}{f''x_{i}} [-f'(x_{i})$ ± $\sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]$

Part B.

It is evident that Newton's method fails in two cases, as:

1. if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)

Part C.

In case $x_{i+1}$ is close to $x_{i}$ , the choice that shouldbe made instead of ± in part A is:

f'(x) = $\sqrt{f'(x)^{2} - 2f(x)f''(x)}$ ⇔ $x_{i+1} = x_{i}$

Part D.

As given $x_{i+1}$ = $x_{i}$ = h

or h = $x_{i+1}$ - $x_{i}$

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also, ( $x_{i+1}$ - $x_{i}$ )² = -( $x_{i+1}$ - $x_{i}$ )(f( $x_{i}$ )/f'( $x_{i}$ ))

So, f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also, $x_{i+1}$ = $x_{i}$ -f( $x_{i}$ )/f'( $x_{i}$ ) + [( $x_{i+1}$ - $x_{i}$ )f''( $x_{i}$ )f( $x_{i}$ )]/[2(f'( $x_{i}$ ))²]

6 0

3 years ago

Which of the followingis multiplicative of -a? (-1/a a 1 1/a)

Elodia [21]

Given:

The given value is $-a$ .

To find:

The multiplicative inverse of $-a$ .

Solution:

We know that $y$ is the multiplicative interval of $x$ if $xy=1$ .

Let $x$ be the multiplicative inverse of the given value $-a$ . Then,

$(-a)\times x=1$

Divide both sides by $-a$ .

$x=\dfrac{1}{-a}$

$x=-\dfrac{1}{a}$

Therefore, the multiplicative inverse of $-a$ is $-\dfrac{1}{a}$ . Hence the correct option is A.

4 0

3 years ago