Volume of A = 1728
volume of B = 729
<span> (1728 / 729) = (a / b)^3 (a = width of A, b = width of B)
a / b = cube root (1728 / 729) = 4/3 </span><span> b = 10 (given)
a / 10 = 4/3 </span><span>
a = 40/3 = 13.33333</span>
so width of A is 13.33m
The domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).
<h3>What are domain and range?</h3>
The domain means all the possible values of the x and the range means all the possible values of the y.
The function is given below.
y = 3/(x + 8)
Then the domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).
More about the domain and range link is given below.
brainly.com/question/12208715
#SPJ1
Answer:
24/35 or 0.6857142
Step-by-step explanation:
The simulation of the medicine and the bowler hat are illustrations of probability
- The probability that the medicine is effective on at least two is 0.767
- The probability that the medicine is effective on none is 0
- The probability that the bowler hits a headpin 4 out of 5 times is 0.3281
<h3>The probability that the medicine is effective on at least two</h3>
From the question,
- Numbers 1 to 7 represents the medicine being effective
- 0, 8 and 9 represents the medicine not being effective
From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two
So, the probability is:
p = 23/30
p = 0.767
Hence, the probability that the medicine is effective on at least two is 0.767
<h3>The probability that the medicine is effective on none</h3>
From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none
So, the probability is:
p = 0/30
p = 0
Hence, the probability that the medicine is effective on none is 0
<h3>The probability a bowler hits a headpin</h3>
The probability of hitting a headpin is:
p = 90%
The probability a bowler hits a headpin 4 out of 5 times is:
P(x) = nCx * p^x * (1 - p)^(n - x)
So, we have:
P(4) = 5C4 * (90%)^4 * (1 - 90%)^1
P(4) = 0.3281
Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281
Read more about probabilities at:
brainly.com/question/25870256
1627190 there's your answer.
