All categories

3 years ago

B) A skilled jet fighter flies a stunt plane in a vertical circle of 1200 ft

Physics

1 answer:

vodka [1.7K]3 years ago

4 0

Answer:I need the ans to this one too

Explanation:

You might be interested in

A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency o

GrogVix [38]

Wave speed = (wavelength) x (frequency)

Wave speed = (0.5 m) x (2 /sec)

<em>Wave speed = 1 m/s</em>

4 0

3 years ago

If heat is gained from a source, it is __________ from the source.

Strike441 [17]

Answer:

Derived, or expended

4 0

3 years ago

Carbon-14 is used to determine the age of ancient objects. If a sample today contains 0.060 g of carbon-14, how much carbon-14 m

MakcuM [25]

Answer: 86.47 g of carbon-14 must have been present in the sample 11,430 years ago.

Explanation:

Half-life of sample of carbon -14= 5,730 days

$\lambda=\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{5,730 days}=0.00012 day^{-1}$

Let the sample present 11,430 years(t) ago = $N_o$

Sample left till today ,N= 0.060 g

$N=N_o\times e^{-\lambda t}$

$ln[N]=ln[N]_o-\lambda t$

$\log[0.060 g]=\log[N_o]-2.303\times 0.00012 day^{-1}\times 11,430 days$

$\log[N_o]=1.9369$

$N_o=86.47 g$

86.47 g of carbon-14 must have been present in the sample 11,430 years ago.

5 0

3 years ago

Read 2 more answers

Mercury is commonly used in thermometer give reasons

evablogger [386]

Answer:

<h3>BECAUSE MERCURY IS USED BECAUSE IT is the only liquid available in room temperature </h3>

Explanation:

pls mark as a BRAINLIST

6 0

3 years ago

Read 2 more answers

A boy whirls a stone in a horizontal circle of radius 1.8 m and at height 1.8 m above level ground. The string breaks, and the s

umka2103 [35]

Answer:

Acceleration is $148.33\ m/s^{2}$

Solution:

As per the question:

Radius of the circle, R = 1.8 m

Height above the ground, h = 1.8 m

Horizontal distance, x = 9.9 m

Now,

The magnitude of the centripetal acceleration can be calculated as:

$a_{c} = \frac{v^{2}}{R}$

where

v = velocity

R = radius

$a_{c}$ = centripetal acceleration

Now, if we consider the vertical component of motion only, then considering the initial velocity, 'u' = 0, from kinematic eqn:

$h = ut + \frac{1}{2}gt^{2}$

$h = 0.t + \frac{1}{2}gt^{2}$

$t = \sqrt{\frac{2h}{g}}$

$t = \sqrt{\frac{2\times 1.8}{9.8}}$

t = 0.606 s

Now, for the horizontal component of velocity:

x = vt

$v =\frac{x}{t}$

$v =\frac{9.9}{0.606} = 16.34\ s$

Now, we know that the centripetal acceleration is given by:

$a_{c} = \frac{16.34^{2}}{1.8} = 148.33\ m/s^{2}$

6 0

3 years ago