Answer:
a
The orbital speed is
b
The escape velocity of the rocket is
Explanation:
Generally angular velocity is mathematically represented as
Where T is the period which is given as 1.6 days =
Substituting the value
At the point when the rocket is on a circular orbit
The gravitational force = centripetal force and this can be mathematically represented as
Where G is the universal gravitational constant with a value
M is the mass of the earth with a constant value of
r is the distance between earth and circular orbit where the rocke is found
Making r the subject
The orbital speed is represented mathematically as
Substituting value
The escape velocity is mathematically represented as
Substituting values
Answer:
wave length is 1.2m
Explanation:
since formula of wave length is v/f
v(speed of sound in air at stp is 300ms^-1)
f(frequency 250hertz)
then wave length is 300÷250 which give 1.2m
Answer:
C1/C2 = 0.213 or C2/C1 = 4.68
Explanation:
Please refer to the attached image for step by step explanation.
Answer:
1098.42 J/kg.c°
Explanation:
Q=mcT
you have : Q = 99100
m=3.47kg
and the change in temperature T = 41-15=26c°
Solve for specific heat c :
c = Q/mT === 99100/3.47(26) = 1098.42J/kg . c°
I hope that it's a clear solution and explanation.
<u>Given:</u>
Enthalpy of dissolution for NaOH = 44 kJ/mol
Mass of NaOH = 12.6 g
Mass of water = 250 g
Initial temperature of water T1 = 23 C
<u>To determine:</u>
The final temperature of water, T2
<u>Explanation:</u>
Molar mass of NaOH = 40 g/mol
# moles of NaOH = 12.6 g/ 40 g.mol-1 = 0.315 moles
Heat released during dissolution of 0.315 moles of NaOH=
= 44 * 0.315 = 13.86 kJ = 13860 J
Heat released by NaOH = heat absorbed by water
13860 = m*c*(T2-T1)
13860 = 250*4.18*(T2-23)
T2 = 36.26 C
Ans: The final temperature of water is 36.3 C