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erik [133]
3 years ago
7

Astronauts in orbit feel weightless because...

Physics
2 answers:
AVprozaik [17]3 years ago
7 0
There is no gravity in orbit/space to pull them toward a certain area so they have full movement and that is why they float

Tatiana [17]3 years ago
4 0
You feel gravity when you feel things pressing together. Like your foot pressing against the floor, or your heart pressing against the inside of your chest. If everything around you is falling just like you are, then you never feel any things pressing together, and that feels like there's no weight.
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The use of force to move an object is <br> .
Ne4ueva [31]
The use of force to move an object is called work. This only applies if the object moves.
4 0
3 years ago
An object is moving in a straight line along the y axis. As a function of time, its position is given by the equation y=3.0+4.8x
romanna [79]

Answer:

Explanation:

<u>Instant Velocity and Acceleration </u>

Give the position of an object as a function of time y(x), the instant velocity can be obtained by

v(x)=y'(x)

Where y'(x) is the first derivative of y respect to time x. The instant acceleration is given by

a(x)=v'(x)=y''(x)

We are given the function for y

y(x)=3.0+4.8x +6.4x^2

Note we have changed the last term to be quadratic, so the question has more sense.

The velocity is

v(x)=y'(x)=4.8+12.8x

And the acceleration is a(x)=v'(x)=12.8

5 0
3 years ago
Are scientific theories and laws developed in the acquisition of scientific knowledge
grigory [225]

Answer:

Scientific theories and laws develop from the acquisition of scientific knowledge.

Explanation:

t

4 0
3 years ago
Photo below with question, please help need to confirm answer<br> Is the answer A?
GarryVolchara [31]

Answer:

Only circuit A will contain to lit bulbs

3 0
3 years ago
a spring gun initially compressed 2cm fires a 0.01kg dart straight up into the air. if the dart reaches a height it 5.5m determi
Vikki [24]

Answer:

2697.75N/m

Explanation:

Step one

This problem bothers on energy stored in a spring.

Step two

Given data

Compression x= 2cm

To meter = 2/100= 0.02m

Mass m= 0.01kg

Height h= 5.5m

K=?

Let us assume g= 9.81m/s²

Step three

According to the principle of conservation of energy

We know that the the energy stored in a spring is

E= 1/2kx²

1/2kx²= mgh

Making k subject of formula we have

kx²= 2mgh

k= 2mgh/x²

k= (2*0.01*9.81*5.5)/0.02²

k= 1.0791/0.0004

k= 2697.75N/m

Hence the spring constant k is 2697.75N/m

7 0
3 years ago
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