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Arisa [49]
3 years ago
9

N which situation is the distance traveled proportional to time?

Mathematics
1 answer:
madam [21]3 years ago
6 0

9514 1404 393

Answer:

  B) biker at 12 mph

Step-by-step explanation:

Distance is proportional to time when velocity is constant. It is not constant in the case of stop-and-go traffic, a baseball*, or a slowing car. The speed of the person biking is given as a constant 12 mph, so that person is traveling a distance proportional to time.

_____

<em>Additional comment</em>

* It depends. The usual assumption is that horizontal speed is constant, in which case the distance from the hitter along the ground is proportional to time. If you are modeling the real world, the ball slows due to air resistance, so distance is not proportional to time.

If you are concerned with the actual distance the baseball travels through the air, the ball's speed slows as it gains height, then increases again as it falls to the ground. The speed is not constant during any part of that travel.

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katovenus [111]

Answer:

-1

Step-by-step explanation:

can be soled by substitution remember BEDMAS

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((-2)-2*(-0.5))^3

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3 years ago
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(I WILL GIVE YOU BRAINLIEST AND ANSWER ALL YOU CAN IDC) a market researcher tracks the number of people who visits a company's w
lawyer [7]

Part A: The exponential function is the best model for the given data. The data shows that every month the number of visitor approximately doubles from previous month. In other words the number is some base value (2, in this case) with the number of month (t) being in the exponent. This the a key characteristic of an exponential growth.  

Part B: (also explained above). Every month the number of visitors approximately doubles. Starting with 5.74 at month 8, the numbers goes up by about the same amount to 12.0 at month 9. At month 10, a similar increase occurs (doubling would be 24, and the data shows 25, so this is all "aproximate"). This trend continues throughout the table.

Part C:

Month 7 will be estimated as half of month 8 (going backward):

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5 0
3 years ago
HELPP PLISS
Otrada [13]

Answer:

C. Tan

Step-by-step explanation:

This is because you are given the measure of the opposite angle and the adjacent side.

7 0
3 years ago
Identify the slope of the line for the equation y= -2/3× + 1/3​
natita [175]

Answer:

\textbf{The slope of the parallel line is given by $ \frac{-2}{3} $}\\

Step-by-step explanation:

\textup{The slope of any two parallel lines are equal and they only differ in their $y- intercepts$. }\\\textup{Given $y = \frac{-2}{3}x + \frac{1}{3} $}\\\textup{This is  comparable to $y = mx + c$, where $m$ is the slope of that line.}\\\textup{Therefore, the slope of the given line and any line parallel to it is $ \frac{-2}{3}$.}

7 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
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