What information is missing to show that ▲WZX ≃ ▲YZX by HL?

For the function F(x) = 1/x+2, which of these could be a value of F(x) when xis

hram777 [196]

Answer:

B 2

Step-by-step explanation:

The computation of the value of f(x) in the case when x = 2 is shown below

As per the question, following function is given

F(x) = (1 ÷ x) + 2

Based on this, the x = 2

Now put the x value in the above equation

So,

= (1 ÷ 2) + 2

= (1 + 4) ÷ 2

= 5 ÷ 2

= 2.5

Hence the closet number is 2

Therefore the value of f(x) in the case when x = 2 is 2

Hence, the correct option is b.

5 0

3 years ago

Read 2 more answers

Brian needs to paint a logo using two right triangles. The dimensions of the logo are shown below. What is the difference betwee

solong [7]

Answer:

7.5 cm²

Step-by-step explanation:

Dimensions of the large ∆:

$base (b) = 3cm, height (h) = 9cm$

$Area = 0.5*b*h = 0.5*3*9 = 13.5 cm^2$

Dimensions of the small ∆:

$base (b) = 2cm, height (h) = 6cm$

$Area = 0.5*b*h = 0.5*2*6 = 6 cm^2$

Difference between the area of the large and the small ∆ = 13.5 - 6 = 7.5 cm²

5 0

3 years ago

Use the distributive property to expand the following expression:

KIM [24]

Answer:

This is guess of what the question is asking:

I had got 49x - 21y - 6.

Step-by-step explanation:

7 x 7 is 49 and 7 x 3 is 21.

4 0

3 years ago

Read 2 more answers

Translate a algebraic expression .four less than four times a number. the translation is? type an expression using x as the vari

kicyunya [14]

4×√·²..................finish

3 0

3 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

1 year ago