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2 years ago

13

How do you write680,705 in expanded form

1 answer:

algol [13]2 years ago

6 0

<span>When you write a number in expanded form you show how much each digit values, according its place in the number. For example, in the number 123, 3 values 3, 2 values 2*10 = 20 and 1 values 1*100 = 100, so the expanded form is 100 + 20 + 3. Using this with 680,705, you have the 6 is in the place of hundreed thousands, 8 is in the place of ten thousands, 0 is in the place fo one thousand, 7 is in the place of hundreeds, 0 is in the place of tens, and 5 is in the place of units. So, the expanded form is: 600,000 + 80,000 + 700 + 5 </span>

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The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

2 years ago

Can anybody help with this?

Sonja [21]

Answer:

12

Step-by-step explanation:

Because < this means less than. So therefore 5 is less than 12

5 0

2 years ago

Write three fractions that are equivalent to 3 over 11 , but written in higher terms. One of them must

Alinara [238K]

Answer:

Three fractions that are equivalent to $\frac{3}{11}$ are: $\frac{6}{22}$ , $\frac{24}{88}$ and $\frac{144}{528}$ .

Step-by-step explanation:

Equivalent fractions are set of fractions in which when simplified, they have the same answer.

Given: $\frac{3}{11}$

i. multiply the numerator and denominator of $\frac{3}{11}$ by 2,

= $\frac{3*2}{11*2}$ = $\frac{6}{22}$

i. multiply both the numerator and denominator of $\frac{6}{22}$ by 4,

= $\frac{6*4}{22*4}$ = $\frac{24}{88}$

ii. multiply the numerator and denominator of $\frac{24}{88}$ by 6,

= $\frac{24*6}{88*6}$ = $\frac{144}{528}$

So that;

$\frac{3}{11}$ = $\frac{6}{22}$ = $\frac{24}{88}$ = $\frac{144}{528}$ .

Three fractions that are equivalent to $\frac{3}{11}$ are: $\frac{6}{22}$ , $\frac{24}{88}$ and $\frac{144}{528}$ .

4 0

3 years ago

The school production of 'Our Town' was a big success. For opening night, 392 tickets were sold. Students paid $3.00 each, w

elixir [45]

Answer:

<u>239 students and 153 non-students attended to the school production of "Our Town"</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets of the school production sold = 392

Student ticket cost = US$ 3

Non-students ticket cost = US$ 5

Total collected = US$ 1,482

2. How many students and how many non-students attended?

For answering the question we will use the following equation:

x = Number of students that attended the school production

392 - x = Number of non-students that attended the school production

3x + (392 - x) * 5 = 1,482

3x + 1,960 - 5x = 1,482

-2x = 1.482 - 1,960

-2x = - 478

x = -478/-2

<u>x = 239 ⇒ 392 - 239 = 153</u>

<u>239 students and 153 non-students attended to the school production of "Our Town"</u>

3 0

2 years ago

Find the area of the figure use 3.14 for pie

frosja888 [35]

What figure? there’s nothing here

7 0

2 years ago

Read 2 more answers