If x is the first integer, then x+1 is the second. x(x+1)=132 or x^2+x-132=0. This factors as (x-11)(x+12)=0. Thus either x=11 or x=-12
<span>So either 11 and 12 or -12 and -11 will do.</span>
We can make use of the general formula for the geometric series to generate the function representing the average annual salary.
an = a0(r)^(n-1)
Or
f(x) = a0(r)^(x - 1)
Plugging in the given values for the year 2005 and 2006 to ge the value of r.
82000 = 70000 (r)^(1-1)
r = 1.1714
Therefore, the function is:
f(x) = 70,000 (1.1714)^(x-1)
There are 3 terms, 5x^2, -3x, and 2
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+
x=(-1)
Let x=0
y+
x=(-1)
y+
(0)=(-1)
y=(-1)
Let x=2
y+
x=(-1)
y+
(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
A) Your primary concerns are the points B and E, so y> .5x+4 and y>or= x-4B) choose one or both points, and enter them into the equations. If the statements are true, then the equations work
for problem C So, any point in the shaded area, but not on the line, are valid points for Natalie's school