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3 years ago

HELP PLS THIS IS HARD

Mathematics

1 answer:

aleksley [76]3 years ago

4 0

Answer:

quadrilateral EFGH is reflected about the x-axis

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Is n+4 equal to 8(n - 4)

weqwewe [10]

No, n+4=4n an 8(n-4)=32n

4 0

3 years ago

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16. Solve for the angle x.<br> cos(¹/2x) = ¹/2

Basile [38]

Answer:

We know that ,

$\rightarrow \tt \cos( \frac{\pi}{3} ) = \frac{1}{2}$

So ,

$\: \rightarrow \tt \cos( \frac{1}{2}x ) = \cos( \frac{\pi}{3} ) \\ \\ \rightarrow \tt \frac{1}{2}.x = \frac{\pi}{3} \\ \\ \rightarrow \tt x = \frac{2\pi}{3}$

we can add 2 pi to it since there will be no change in the value

Also,

$\: \rightarrow \tt \cos( \frac{14\pi}{6} ) = \frac{1}{2} \\ \\ \\ \rightarrow \tt \frac{1}{2} x = \frac{14\pi}{6} \\ \\ \rightarrow \tt x = \frac{7\pi}{3}$

Answer : Option B

6 0

2 years ago

Angela decides to recycle a large oatmeal container by using it to hold a friends birthday gift. Then she wraps the container in

Deffense [45]

Answer:

D. 135.37 in²

Step-by-step explanation:

We have that the gift paper consists of two circles and a square.

Thus, we will need to find the area of the circles and the square.

Now, as the diameter of the circle = 4 inches

So, the radius of the circle = $\frac{4}{2}$ = 2 inches

Since, the area of a circle = $\pi r^{2}$

This implies that area of the two circles = $2\times \pi r^{2}$

i.e. Area of the circles = $2\times \pi 2^{2}$

i.e. Area of the circles = $8\pi$

i.e. Area of the two circles = 25.133 in²

Further, one side of the square = 10.5 inches

Thus, the area of the square = $side^{2}$

i.e. Area of the square = $10.5^{2}$

i.e. Area of the square = 110.25 in²

So, the overall area of the gift paper = 25.133 + 110.25 = 135.37 in².

Hence, the amount of paper used by Angela is 135.37 in².

7 0

3 years ago

Rearrange the formula C = 5/9 (F − 32) for F.

shtirl [24]

The answer is (9c/5)+32=F

5 0

3 years ago

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What are the zeros of the polynomial function f(x) = x^3-10x^2+24x

Ludmilka [50]

Replace F(x) with y
y=x^3-10x^2+24x
To find the roots replace y with 0.
0=x^3-10x^2-24x
Rewrite the equation as
x^3-10x^2+24x=0
Factor the left side
x(x-6)(x-4)=0
The solution is a result of
x=0, x-6=0, and x-4=0

The answer is:
x=0, 6, 4

3 0

3 years ago