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erica [24]
3 years ago
7

Could somebody help me on the 2 question please

Mathematics
2 answers:
ozzi3 years ago
8 0
-20 because after the the thermometer hits zero the more negative the temperature gets the colder it is
Nataliya [291]3 years ago
8 0

Answer:

<h3>on question 2 the one which you need to write<em> is -20 degrees bcz it's colder than -10 degrees </em></h3>

Step-by-step explanation:

where is the question 1

+this sentence :"<em> is -20 degrees bcz it's colder than -10 degrees "is a 2answer sentence</em>

<em>hope this helps</em>

<em></em>

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The sum of a whole number and twice the square of the number is 10. Find the number.
sveticcg [70]

Answer:

x = \frac{10}{1 + 2x}

Step-by-step explanation:

Let the number be x

x + 2x² = 10

Factorize x + 2x²

x(1 + 2x) = 10

Divide both sides by (1 + 2x)

x = \frac{10}{1 + 2x}

6 0
3 years ago
A triangular window pane has a base of 30 inches and a height of 24 inches.What is the area of the window pane?
densk [106]

54 or it 180 i got 54 by adding 30 and 24in and got 180 by multiplying

8 0
2 years ago
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Pls help me!!! I don’t know the answer I will give u brainlyest if I get it correct
inna [77]

Answer:

C?

Step-by-step explanation:

5 0
2 years ago
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400 m in 32 s - runners speed
Harman [31]

Answer:

12.5 m in 1 second.

Step-by-step explanation:

400/32=12.5

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2 years ago
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A bean plant grows at a constant rate for a month. After 10 days, the plant is
777dan777 [17]

Answer:

B. y - 35 = 2(x - 10)

Step-by-step explanation:

The height of the plant, y, after x days could be modeled by the equation

<h3>y-y0=k(x-xo)     (1),</h3><h3>where y0 was the initial height at 'x0'th. day, and k is the constant of proportionality.</h3><h3>From equation (1), k could be evaluated as follows:</h3><h3>k=(y-y0)/(x-x0) </h3><h3>From the problem statement, we may determine k by plugging in the given values, e.g. y0= 35, x0=10, y=55, x=20.</h3><h3>Thus,</h3><h3>k=(55-35)/(20-10)=2</h3><h3>Therefore, the model equation becomes</h3><h3>y-35=2(x-10)</h3><h3></h3>

6 0
3 years ago
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