Answer:
I will make 8 slices....
because I do love it....
it depends on you and ur choice how many pieces of what type of shape you want to have...
Answer:
The correct answer is - 1/41,493
Explanation:
Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:
2pq + 2pqF. ( where F is the inbreeding coefficient).
The frequency of the two different hoozygotes in inbred population can be calculated as:
p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.
Given: Frequency of Alkaptonuria (q 2) = 1:500, 000
=> q = 1/707
p = 706/707 ( Approx values)
solution:
Inbreeding coefficient (F) = 1/64
Therefore,
Frequency of Alkaptonuria in second cousins= q 2 + pqF
= 1/500, 000 + (706/707 x 1/707) x (1/64)
= 1/500, 000 + 1/45, 248
= 1/41,493 (approx)
AA
AB
A0
BB
B0
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^all the possible outcomes
A
AB
B
^basics
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Answer:
They can destroy the ecosystem or out - compete a native species.
Explanation:
For example, if an invasive species of tree is taller than the native species of tree and therefore takes up more sunlight, leaving the shorter native tree not enough sun, then it will effectively kill the native tree.
Also non - native and invasive are not the same thing. A non - native species doesn't necessarily mean it's invasive. It is only invasive if it begins to have a significant impact on the ecosystem it is inhabiting.
Answer:
Helium and carbon dioxide
