All categories

3 years ago

What kind of solution is x(5 - 2) = 4x - x

Mathematics

2 answers:

Novay_Z [31]3 years ago

3 0

Answer:

x=x or it cancels out, it's one of those.

SashulF [63]3 years ago

3 0

Infinitely many solutions
X(5-2) = 4x-x
5x-2x=4x-x
3x=3x

You might be interested in

Solve the system of equations and choose the correct answer from the list of options.

SpyIntel [72]

(3, -2) satisfies both equations. 3-2=1, and -3-2=-5.

7 0

3 years ago

Read 2 more answers

Log(4) 5 + log (4) ? =log(4) 35

kolezko [41]

Step-by-step explanation:

logwjqjqjhajqjqjsjwjqjqjqjnqnqnqnqnqnqnqnq

3 0

3 years ago

Read 2 more answers

Which equation is a linear equation? y=2x2+3 y=2/x+3 y=2x+3 y=2x+3

Setler [38]

Y=2x+3 is a linear equation.

8 0

3 years ago

Exercise 1.A committee of five people is chosen randomly from four men and six women. Find the probability that:a) Exactly four

MatroZZZ [7]

Answer with explanation:

Given : Number of men = 4

Number of women = 6

Total people = $6+4=10$

Total number of ways to make a committee of five people from 10 persons :-

$^{10}C_{4}=\dfrac{10!}{4!(10-4)!}=210$

a) Number of ways to make committee that has exactly four women :

$^6C_4\times ^4C_1=\dfrac{6!}{4!(6-4)!}\times4=60$

The probability that committee has exactly four women :

$\dfrac{60}{210}=\dfrac{2}{7}$

b) Number of ways to make committee that has at-least four women :

$^6C_4\times ^4C_1+^6C_5=\dfrac{6!}{4!(6-4)!}\times4+6=66$

The probability that committee at-least four women :

$\dfrac{66}{210}=\dfrac{22}{70}$

c) Number of ways that committee has more than 4 women :-

$^6C_5\times^4C_0=6$

The probability that committee has more than 4 women :-

$\dfrac{6}{210}$

Now, the probability that committee has at most four women :-

$1-\dfrac{6}{210}=\dfrac{204}{210}=\dfrac{102}{105}$

5 0

3 years ago

Can you guys please do both with the work please and thank you if you actually do it

salantis [7]

Answer:

7. 29 cm

8. equation: 61 = (x) +(2x -7) +(3x +2); sides 11, 15, 35

Step-by-step explanation:

7. Let w represent the width. The length is 3 less than twice the width, so the length is 2w-3. The perimeter is given by the formula ...

P = 2(L+W)

Substituting the known values, we have ...

90 = 2((2w-3) +w)

45 = 3w -3 . . . . . . . . divide by 2

15 = w - 1 . . . . . . . . . .divide by 3

16 = w . . . . . . . . . . . . add 1

L = 2w -3 = 2(16) -3 = 29

The length of the rectangle is 29 cm.

8. The equation that should be used is the one that relates the side lengths to the perimeter.

P = a + b + c . . . . for sides a, b, c

61 = (x) +(2x -7) +(3x +2)

61 = 6x -5 . . . . . . collect terms

66 = 6x . . . . . . . . add 5

11 = x . . . . . . . . . . divide by 6

Then the side lengths are ...

a = x = 11

b = 2x -7 = 2(11) -7 = 15

c = 3x +2 = 3(11) +2 = 35

_____

Comment on problem 8

You will notice that the side lengths do not satisfy the triangle inequality: the sum of the short sides is not greater than the long side. These side lengths cannot form a triangle. Cute algebra, but bad geometry.

4 0

3 years ago