Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.
The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02
Part A:
</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:
</span>

<span>
Part B:
The mean of a binomial distribution is given by
</span>

<span>
The standard deviation is given by:
</span>

<span>
Part C:
This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
Answer:
hmmmm bilmim weantremlo ?
Answer:
X= 3 or x=-17
Step-by-step explanation:
1. Simplify both sides of the equation
2. Subtract 4X to the second power +56X +192 from both sides
3. Factors the left side of the equation
4. Set factors equal to zero
Answer:
a) 820
b)450
c) -540
d) -294
e) 1440
f) 1425
Step-by-step explanation:
a) it is an arithmetic progression with ratio=4
a1=3,
a2=3+r=3+4=7.....
a20=a1+19r
so a20=3+19*4=3+76=79
S=(a1+an)*n/2 where n=20
so S=(3+79)*20/2=820
b) a15=a1+14*r=2+14*4=2+56=58
S=(a1+a15)*15/2=(2+58)*15/2=60*15/2=30*15=450
It is the same formula for all the exercises
S=(a1+an)*n/2 , where n is the number of terms
c) a40=30+39*(-3)=30-87=-57
So S=(30-57)*40/2=-540
d) a14=5+13*(-4)=5-52=-47
S=(5-47)*14/2=-42*14/2=-42*7=-294
e) it is 5+7+9+......+75
nr of terms = (an-a1) :r+1=(75-5):2+1=36
S=(5+75)*36/2=36*40=1440
f) ratio=7-4=3
the same formula for n= (91-4):3+1=87:3+1=29+1=30
S=(4+91)*30/2=95*30/2=2850/2=1425
Using PEDMAS, you would divide I/2 first, then add 2 to that and subtract I from the equation. It all varies on what "i" is, however.