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DiKsa [7]
3 years ago
7

Noah is running a portion of a marathon at a constant speed of 6 miles per hour.

Mathematics
2 answers:
Anastasy [175]3 years ago
5 0
If Noah is running 6 miles an hour then we know that for every hour, he is running 6 miles. You have to multiply each hour he’s running by 6.

For the last three answers, since they give you how much time he ran, you have to divide by 6 miles.

Answers:
1 = 6
1/2 = 3
1 1/3 = 8
(I can’t see the fourth one)
1 1/2 = 9
3/4 = 4 1/2

ololo11 [35]3 years ago
3 0
I can only see the numbers for the top half of the table. If you tell me what the bottom half of the table, I will do it.

Time in Hours miles traveled
6 hours 6 miles
1/2 hours 3 miles
1 1/3 8 miles
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1. Solve for w in the equation W/5 = 25<br> A.W = 5<br> B.W = 125<br> C. W = 30<br> D.W = 20
vekshin1

Answer: <em>w = 125</em>

Explanation: Since <em>w</em> is being divided by 5, to solve for <em>w</em>,

multiply both sides of the equation by 5.

On the left side, the 5's will cancel

and on the right side, 25(5) is 125.

So <em>w = 125</em>.

<u />

<u>Please do not do this problem in your head.</u>

Show the work that it takes to get <em>w</em> by itself.

3 0
3 years ago
A system of equations consists of a line s of the equation y = x – 5 and a line t that passes through the points (0, 2) and (8,
GenaCL600 [577]

Answer:

\text{The slope of the line t:}\ m=-\dfrac{3}{4}\\\\\text{The y-intercept of the line t:}\ b=2\\\\\text{The equation of a line t in the slope-intercept form:}\ y=-\dfrac{3}{4}x+2

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept → (0, b)

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (8, -4) and (0, 2) → b = 2.

Calculate the slope:

m=\dfrac{2-(-4)}{0-8}=\dfrac{6}{-8}=-\dfrac{3}{4}

Therefore the equation of a line t in the slope-intercept form is:

y=-\dfrac{3}{4}x+2

5 0
3 years ago
Read 2 more answers
1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves
erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx

\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx

\ln|y| = x - \ln|x+1| + C

When x = 0, we have y = 2, so we solve for the constant C :

\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)

Then the particular solution to the DE is

\ln|y| = x - \ln|x+1| + \ln(2)

We can go on to solve explicitly for y in terms of x :

e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}

(b) The curves y = x² and y = 2x - x² intersect for

x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1

and the bounded region is the set

\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}

The area of this region is

\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}

7 0
2 years ago
The glass window pane has an area of 80 square centimeters. The width of the pane is 8 centimeters.
Brums [2.3K]

Answer:

The length is 10 cm

Step-by-step explanation:

The area is given by length times width

A = l*w

We have an area of 80 cm^2 and a width of 8

80 = l*8

Divide each side by 8

80/8 = 8l/8

10 = l

The length is 10 cm

6 0
3 years ago
Read 2 more answers
A clothing manufacturer uses the model a=f+4−−−−√−36−f−−−−−√ to estimate the amount of fabric to order from a mill. In the formu
Anit [1.1K]

Questions:

A clothing manufacturer uses the model a = √(f + 4) - √(36 - f) to estimate the amount of fabric to order from a mill. In the formula, a is the number of apparel items (in hundreds) and f is the number of units of fabric needed. If 400 apparel items will be manufactured , how many units of fabric should be ordered?

Answer:

32 units of fabrics

Step-by-step explanation:

Given

a = \sqrt{f + 4} - \sqrt{36 - f}

Required

Find f when a  = 4

Substitute 4 for a

4 = \sqrt{f + 4} - \sqrt{36 - f}

Rewrite as:

\sqrt{36 - f} + 4 = \sqrt{f + 4}

Square both sides

(\sqrt{36 - f} + 4)^2 = (\sqrt{f + 4})^2

(\sqrt{36 - f} + 4)^2 = f + 4

36 - f + 8\sqrt{36 - f} + 16 = f + 4

Collect Like Terms

8\sqrt{36 - f}= f +f+ 4 - 36 -16

8\sqrt{36 - f}= 2f -48

Divide through by 2

4\sqrt{36 - f}= f -24

Square both sides

16(36-f) = (f - 24)^2

16(36-f) = f^2 - 48f + 576

576-16f = f^2 - 48f + 576

-16f = f^2 - 48f

Collect like terms

f^2 - 48f + 16f = 0

f^2 -32f = 0

Factorize

f(f - 32) = 0

f = 0 or f = 32

f can not be 0 because some units must be ordered.

So, f = 32

6 0
3 years ago
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