Answer:
157
Step-by-step explanation:
We are given that
Number of students in maths 2A=n(2A)=51
Number of students in math 2B=n(2B)=80
Number of students in math 2C=n(2C)=70
Number of students in maths 2A and 2B=
Number of students in maths 2B and 2C=
Number of students in maths 2A and 2C=
Number of students in maths 2A ,2B and 2C=4
We have to find the number of students in a set.
Formula:
Substitute the values in the given formula

Hence, total number of students in a set=157
Answer:
1
Step-by-step explanation:
13 x 4 = 52
53 - 52 = 1
ans
here let mary age be x and fred be y
1st equation
x= 5y
2nd equation
x+3 =4(y+3)
now from 1st equation putting value of x in equation 2
x+3 = 4y+12
5y+3 = 4y +12
y = 9
so fred is 9 and mary is 45
As a customer allison buy jeans; and as a tailor allison makes t shirts. so she plays both roles
Answer:
about 252.78 ft
Step-by-step explanation:
Define angle QMP as α. Then ...
MN = 60·sin(α)
NP = 60·cos(α)
area MPN = (1/2)(MN)(NP) = 1800sin(α)cos(α)
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PQ = 60tan(α)
area MPQ = (1/2)(MP)(PQ) = 1800tan(α)
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The ratio of areas is 2.5, so we have ...
1800tan(α) = 2.5·1800sin(α)cos(α)
1 = 2.5cos(α)² . . . . . . divide by 1800tan(α)
cos(α) = √0.4 . . . . . . solve for cos(α)
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Then the perimeter is ...
Perimeter = MN +NP +PQ +QM = 60sin(α) +60cos(α) +60tan(α) +60/cos(α)
= 60(sin(α) +cos(α) +tan(α) +sec(α))
= 60(0.774597 +0.632456 +1.224745 +1.581139)
= 60(4.212936) = 252.776
The perimeter of the trapezoid is about 252.776 feet.
_____
With perhaps a little more trouble, you can find the exact value to be ...
perimeter = (6√10)(7+√6+√15)